Thanks, Y On Fri, Jul 20, 2012 at 1:02 PM, arun <smartpink...@yahoo.com> wrote:
> Hi, > > Try this: > dat1<-read.table(text=" > id date a b c y > 1 1 8/6/2008 Red 15 B 22 > 2 1 8/6/2008 Green 15 B 22 > ",sep="",header=TRUE) > dat1$date<-with(dat1,as.factor(date)) > dat1 > id date a b c y > 1 1 8/6/2008 Red 15 B 22 > 2 1 8/6/2008 Green 15 B 22 > is.factor(dat1$date) > [1] TRUE > A.K. > > > > ----- Original Message ----- > From: Yolande Tra <yolande....@gmail.com> > To: r-help@r-project.org > Cc: > Sent: Friday, July 20, 2012 10:44 AM > Subject: [R] convert date to a factor > > Hello, > > I would like to convert date as a factor to represent time in a repeated > measure situation in the following code. How would I do that? > > d <- read.csv(file.path(dataDir,"data.csv"), as.is=T,stringsAsFactors = > FALSE) > > d[1:2,] > id date a b c y > 1 1 8/6/2008 Red 15 B 22 > 2 1 8/6/2008 Green 15 B 22 > Thank you, > Y > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html> > and provide commented, minimal, self-contained, reproducible code. > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
