ok
site1 site2 site3 site4
species1 1 2 3 4
species2 3 0 4 5
species3 5 3 7 3
spesies4 0 3 6 7
species1 species2 species3 species4
site1 1 3 5 0
site2 2 0 3 3
site3 3 4 7 6
site4 4 5 3 7
this is what I want to do. It is hard to learn R as I have never programed
anything in my life, but I am learning slowly. I am a researcher who finds
statistics indispensable. I apologize for my flawed logic but this is what
I want to do.
x <- read.table("file.csv", sep=",", header=T)
it is is correct I just want to flip the rows and columns. How do I do
this? sorry for my lack of understanding. All help is greatly appreciated.
Stephen
On Tue, Apr 15, 2008 at 7:08 PM, Rolf Turner <[EMAIL PROTECTED]>
wrote:
>
> RML: *** Data frames are NOT matrices!!! ***
>
> On 16/04/2008, at 10:35 AM, stephen sefick wrote:
>
> x <- read.table("LittleGarvin.csv", sep=",", header=TRUE)
> > y <- t(x)
> > str(y)
> >
> > chr [1:193, 1:288] "oligocha" "0" " 0" " 0" " 0" "0" ...
> > - attr(*, "dimnames")=List of 2
> > ..$ : chr [1:193] "X" "upwd1201" "upwd0502" "upwd0702" ...
> > ..$ : NULL
> >
> > x is a data frame with a whole bunch of numeric vectors I would like for
> > the
> > rows and columns to be reversed == transposed but with the same
> > attributes.
> > I am trying to feed the transposed data frame to metaMDS(vegan). I am
> > stumped- sorry for the large attached file- I am at a loss.
> >
>
> Although it is possible, transposition makes little to no sense
> for data frames. If you want to transpose something you are
> thinking of it as being a *matrix* not a data frame. The result
> of transposing a data frame is in fact a matrix.
>
> There is as far as I know no structure in R whereby the rows of
> a matrix-like object can have different characteristics. (The
> term ``attributes'' has a technical meaning in R which is probably
> not what you intend --- but even if you do intend that, it's not
> possible.)
>
> The complaint made in your subject line is that the result of
> your transposition is not numeric. It is in fact character.
> That's because there is character data in the data frame x.
> When you transpose x, it is first coerced into a matrix. If there
> are any character or factor columns in x the coercion will result
> in a character matrix, the transpose of which will of course be a
> character matrix.
>
> The solution is of course to remove the character or factor columns
> from x before transposition.
>
> If you ``can't'' do this, then you ***can't*** transpose ---
> transposition
> just doesn't make any sense at all. Simple as that.
>
> cheers,
>
> Rolf Turner
>
>
>
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little or so large that all they really do for us is puff us up and make us
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