Sorry, not one of my days. Forgot to Cc the list.
Rui barradas
Em 10-10-2012 20:28, Sarah Goslee escreveu:
Sent just to me?
On Wed, Oct 10, 2012 at 3:26 PM, Rui Barradas <ruipbarra...@sapo.pt> wrote:
You're right, apologies to the op and the list. I was thinking of the more
complicated
as.numeric(levels(abc)[abc[1]])
Rui Barradas
Em 10-10-2012 19:58, Sarah Goslee escreveu:
Rui, that doesn't answer the question as I understood it:
Your suggestion returns the numeric value of the second value of the
levels:
as.numeric(levels(abc)[2])
[1] 3
But I read the question as wanting the numeric value of the second
element of abc:
as.numeric(as.character(abc[2]))
[1] 2
On Wed, Oct 10, 2012 at 2:52 PM, Rui Barradas <ruipbarra...@sapo.pt>
wrote:
Hello,
Try instead
?levels
abc <- factor(c(2,2,3,4,7,7))
as.numeric(levels(abc)[1])
Hope this helps,
Rui Barradas
Em 10-10-2012 19:39, Brigid Mooney escreveu:
Sorry, I'm sure I'm not using the appropriate vocab here, which is
undoubtedly why I can't seem to find a fix to this (hopefully very
easy) problem.
Suppose you have a factor
abc <- factor(c(2,2,3,4,7,7))
And you want to know what the number in the nth spot in that would be
abc[1]
[1] 2
Levels: 2 3 4 7
shows the correct label of the first element - but if I want to pull
out the numeric value of that label, I thought...
as.numeric(abc[1])
but that gives
[1] 1
which is the position of the label in the levels vector of the factor.
Ideas?
Thanks!
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