On Oct 12, 2012, at 1:07 AM, Henri-Paul Indiogine wrote:

> Hi Michael!
> 
> 2012/10/12 R. Michael Weylandt <michael.weyla...@gmail.com>:
>> If they are already in decreasing order, you might be able to work
>> something out like (untested):
>> 
>> cumsum(c(1, diff(x) < 0))
> 
> Thanks seems to work.  Thanks a bunch!

Another strategy:

cumsum(!duplicated(x))

-- 

David Winsemius, MD
Alameda, CA, USA

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