Off-list it was pointed out to me that the trivial solution to this would look like this: myfunction2 <- function(x, ...){ mylist <- list(x, ...) # plenty of "lapply" stuff do.call(vioplot,mylist) }
Thanks for everybodies patience, Joh Johannes Graumann wrote: > <posted & mailed> > > Thanks for the very appropriate scolding. > > Here's my example (based on "?vioplot"): > mu<-2 > si<-0.6 > bimodal<-c(rnorm(1000,-mu,si),rnorm(1000,mu,si)) > uniform<-runif(2000,-4,4) > normal<-rnorm(2000,0,3) > # Working just fine > myfunction1 <- function(x, ...){vioplot(x,...)} > myfunction1(bimodal,uniform,normal) > # What I (believe to) need > myfunction2 <- function(x, ...){ > mylist <- list(x, ...) > # plenty of "lapply" stuff > vioplot(mylist) > } > myfunction2(bimodal,uniform,normal) > --> Error in min(data) : invalid 'type' (list) of argument > > I'm at a loss on how to disentangle "mylist" - unlist just gives me one > big vector back rather than the 3 I want to have back ... > > Thanks for your patience, Joh > > jim holtman wrote: > >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html and provide commented, >> minimal, self-contained, reproducible code. >> >> It is hard to provide a solution if we do not understand the problem >> to be solved. Sample data would be helpful along with an >> understanding of what you would expect for output. >> >> On Wed, Apr 23, 2008 at 10:11 AM, Johannes Graumann >> <[EMAIL PROTECTED]> wrote: >>> >>> Johannes Graumann wrote: >>> >>> > Hi, >>> > >>> > I have a list of vectors and am trying to coerce them into something >>> > that vioplot will take as groups of data to be plotted independently. >>> > Can someone nudge me into the right direction? >>> > >>> > Thanks, Joh >>> > >>> > ______________________________________________ >>> > R-help@r-project.org mailing list >>> > https://stat.ethz.ch/mailman/listinfo/r-help >>> > PLEASE do read the posting guide >>> > http://www.R-project.org/posting-guide.html and provide commented, >>> > minimal, self-contained, reproducible code. >>> >>> I'll try less impolite and with more info ... >>> >>> I'm writing a function that contains this: >>> >>> # function(x, ... , morestuff){} >>> >>> which is gathered into a list like so: >>> >>> # mylist <- list(x, ...) >>> >>> down the line I'd like to output all elements from "mylist" in seperate >>> vioplots in a single coordiante system. Now I have a hell of a time with >>> that because vioplot does not accept a list as input but only a >>> succession of vectors ... how can I now force my list into that form so >>> a can say >>> >>> # vioplot(magicfunction(mylist)) >>> >>> and get a violin plot for each list-member? >>> >>> Thanks for any hint, >>> >>> >>> Joh >>> >>> ______________________________________________ >>> R-help@r-project.org mailing list >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html and provide commented, >>> minimal, self-contained, reproducible code. >>> >> >> >> > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html and provide commented, > minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.