responding to my own question, I see in ?svm man it states fitted() and predict() can do the same thing:
# test with train data pred <- predict(model, x) # (same as:) pred <- fitted(model) On Nov 21, 2012, at 1:08 AM, signal <bfe...@mac.com> wrote: > Did you ever receive a response to this? I did not see one public. > > I would think that if your dataset was of a large enough size, that 10-fold > validation would show an improvement over N:N. > > Also, any ideas if there is any difference really in using fitted() vs. > predict() in your second step? I am pretty sure they do the same thing. > > Brian > > > > -- > View this message in context: > http://r.789695.n4.nabble.com/e1071-SVM-Cross-validation-error-confusion-matrix-tp4437047p4650252.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
