On Dec 1, 2012, at 9:55 AM, R. Michael Weylandt wrote:
15 < a & a < 20
Wrap it in a function if you like:
in_interval <- function(x, interval){
stopifnot(length(interval) == 2L)
interval[1] < x & x < interval[2]
}
in_interval(a, c(15, 20))
Could just use the findInterval function:
findInterval(x, c(15,20) ) == 1
findInterval returns a numeric vector indicating which bin(s) the
argument vector element(s) fall(s) into. Items below the lower bound
get a zero which means if the result is used as an index the there
will be no item chosen for that value. Items above the maximal
boundary get a value of n+1 where n is the number of bins. (Very
useful function.)
--
David.
Cheers,
Michael
On Sat, Dec 1, 2012 at 4:50 PM, Andras Farkas <motyoc...@yahoo.com>
wrote:
could you please give me some pointers on how I could make R screen
for a value if it falls within a certain range?
I looked at the subset function, but is not doing it, perhaps
because I only have 1 value to screen?
aptreciate the input
ex:
a <-16.5
I would like to screen to see if a is within the range of 15 to 20,
(which it is:-)), and I would like the code to return a value of 1
if a is within the specified range or 0 if it is not.
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David Winsemius, MD
Alameda, CA, USA
______________________________________________
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and provide commented, minimal, self-contained, reproducible code.
