Hello,

Something like this?


dat <- read.table(text="
20100914 08:01     3.74
20100914 08:11     3.74
20100914 08:21     3.71
20100914 08:31     4.39
20100914 08:41     3.74
")
dat

split(dat$V3, dat$V1)


This gives you a list where each element is a (1-dimensional) vector, and each of those vectors can have any length, not necessarily the same.

Hope this helps,

Rui Barradas
Em 22-12-2012 10:58, Matthijs Daelman escreveu:
Hi

I have a time series of measurements: every 10 min. a value was logged.

The data look like:

20100914 08:01     3.74
20100914 08:11     3.74
20100914 08:21     3.71
20100914 08:31     4.39
20100914 08:41     3.74

This data spans several months.

I would like to group the data per day. In Matlab it is fairly easy to obtain a cell array, of which the first column contains the date of each day, and the second column contains a vector, that in its turn contains all values for the corresponding day.

That looks like

14-9-2010    [3.74 3.74 3.71 4.39 3.74...]
15-9-2010    [...]
and so on.

Is it possible to create a similar data structure in in R? I was thinking of a data frame, similar to the Matlab's cell array, but it doesn't look like data frames can contain vectors. Something like a two dimensional list would do the trick, I believe, but does that exist?

Thanks

Kind regards

Matthijs Daelman

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to