You can try this one too. #Set the directory to a path where all the files to be read are stored
TabletoRead=list.files(pattern=".txt") I_Step=unlist(lapply(TabletoRead,function(tab){ srno<<-ifelse(exists("srno"),(1+srno),1) Temp=read.table(tab,header=T,sep="#Seperator") makeActiveBinding(paste("Table",srno,sep="_"), function() Temp, .GlobalEnv) })) rm(I_Step) Ref_Table=cbind(Orignial=TabletoRead,Stored_As=paste("Table",1:length(TabletoRead),sep="_")) #When required you can check the Ref_Table to get the required table On Thu, Dec 20, 2012 at 10:41 AM, Jeff Newmiller <jdnew...@dcn.davis.ca.us>wrote: > The short answer is: don't try. You really don't want dozens of different > objects in memory that you didn't name yourself. > > What you want instead is a list of objects. You can start with a vector of > filenames and use lapply to create another list containing the data frames. > For convenience you can then set the list element names to the names of the > files. > > fnames <- list.files() > dta <- lapply( fnames, function(i){read.table(i, header= TRUE) }) > names(dta) <- fnames > > You can access these data frames using the $ or "[[" operators. > > dta$G1.txt > dta[["G1.txt"]] > or > dta[[2]] > > Read more about it in the Introduction to R document supplied with R. > --------------------------------------------------------------------------- > Jeff Newmiller The ..... ..... Go Live... > DCN:<jdnew...@dcn.davis.ca.us> Basics: ##.#. ##.#. Live > Go... > Live: OO#.. Dead: OO#.. Playing > Research Engineer (Solar/Batteries O.O#. #.O#. with > /Software/Embedded Controllers) .OO#. .OO#. rocks...1k > --------------------------------------------------------------------------- > Sent from my phone. Please excuse my brevity. > > Yao He <yao.h.1...@gmail.com> wrote: > > >Dear All > > > >I have a lot of files in a directory as follows: > >"02-03.txt" "03-04.txt" "04-05.txt" "05-06.txt" "06-07.txt" > >"07-08.txt" "08-09.txt" > > "09-10.txt" "G0.txt" "G1.txt" "raw_ped.txt" > >.......................... > > > >I want to read them into different objects according to their > >filenames,such as: > >02-03<-read.table("02-03.txt",header=T) > >03-04<-read.table("03-04.txt",header=T) > >I don't want to type hundreds of read.table(),so how I read it in one > >time? > >I think the core problem is that I can't create different objects' > >name in the use of loop or sapply() ,but there may be a better way to > >do what I want. > > > >Thanks a lot > > > >Yao He > > > >Yao He > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.