Hello,

try the following.

test.df$Var1 <- seq(0,1, by=0.05)[-1]
test.df


Hope this helps,

Rui Barradas

Em 24-01-2013 17:39, Wim Kreinen escreveu:
Hello,

I have a dataframe (test.df) with intervals that were generated by table
(see below). I would prefer a dataframe labeled like this:


test.tab <- table(cut(skn.test$density, seq (0,1, by=0.05)))
test.tab

   (0,0.05] (0.05,0.1] (0.1,0.15] (0.15,0.2] (0.2,0.25] (0.25,0.3]
(0.3,0.35]
         68         87         85         72         65         73
74
(0.35,0.4] (0.4,0.45] (0.45,0.5] (0.5,0.55] (0.55,0.6] (0.6,0.65]
(0.65,0.7]
         72         77         78         75         74         83
93
(0.7,0.75] (0.75,0.8] (0.8,0.85] (0.85,0.9] (0.9,0.95]   (0.95,1]
         89         75         67         59         56        208
test.df <- as.data.frame (test.tab)
test.df
          Var1 Freq
1    (0,0.05]   68
2  (0.05,0.1]   87
3  (0.1,0.15]   85
4  (0.15,0.2]   72
5  (0.2,0.25]   65
6  (0.25,0.3]   73
7  (0.3,0.35]   74
....


I would prefer a dataframe labelled like this.
0.05    68
0.1      87


How to do?
Thanks
Wim


dput (test.tab)
structure(c(68L, 87L, 85L, 72L, 65L, 73L, 74L, 72L, 77L, 78L,
75L, 74L, 83L, 93L, 89L, 75L, 67L, 59L, 56L, 208L), .Dim = 20L, .Dimnames =
structure(list(
     c("(0,0.05]", "(0.05,0.1]", "(0.1,0.15]", "(0.15,0.2]", "(0.2,0.25]",
     "(0.25,0.3]", "(0.3,0.35]", "(0.35,0.4]", "(0.4,0.45]", "(0.45,0.5]",
     "(0.5,0.55]", "(0.55,0.6]", "(0.6,0.65]", "(0.65,0.7]", "(0.7,0.75]",
     "(0.75,0.8]", "(0.8,0.85]", "(0.85,0.9]", "(0.9,0.95]", "(0.95,1]"
     )), .Names = ""), class = "table")

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