Hi, I am not sure why you are getting different results. I couldn't reproduce your problem. dat1<- read.table(text=" ID COMPL SEX HEREDITY 1 0 1 2 1 0 1 2 1 3 1 2 2 0 0 1 2 1 0 1 2 2 0 1 2 2 0 1 3 0 0 1 3 0 0 1 3 0 0 1 3 0 0 1 3 2 0 1 4 0 1 2 4 0 1 2 ",sep="",header=TRUE) do.call(rbind,lapply(split(dat1,dat1$ID),function(x) if(any(x$COMPL!=0)) head(x[x$COMPL!=0,],1) else head(x,1))) # ID COMPL SEX HEREDITY #1 1 3 1 2 #2 2 1 0 1 #3 3 2 0 1 #4 4 0 1 2
You could also try: dat1[with(dat1,ave(COMPL,ID,FUN=function(x) if(any(x!=0)) cumsum(x>0) else seq_along(x)))==1,] #modification of David's code # ID COMPL SEX HEREDITY #3 1 3 1 2 #5 2 1 0 1 #12 3 2 0 1 #13 4 0 1 2 A.K. ________________________________ From: Tasnuva Tabassum <t.tasn...@gmail.com> To: arun <smartpink...@yahoo.com> Sent: Sunday, February 24, 2013 12:08 AM Subject: Re: [R] Selecting First Incidence from Longitudinal Data sorry, I tried this. But it gave me answer: # ID COMPL SEX HEREDITY #1 1 0 1 2 #4 2 0 0 1 #8 3 0 0 1 #13 4 0 1 2 On Sat, Feb 23, 2013 at 8:44 PM, arun <smartpink...@yahoo.com> wrote: Hi, >Try this: >#dat1 > do.call(rbind,lapply(split(dat1,dat1$ID),function(x) if(any(x$COMPL!=0)) >head(x[x$COMPL!=0,],1) else head(x,1))) > ># ID COMPL SEX HEREDITY > >#1 1 3 1 2 >#2 2 1 0 1 >#3 3 2 0 1 >#4 4 0 1 2 >A.K. > > > > > > >________________________________ >From: Tasnuva Tabassum <t.tasn...@gmail.com> >To: Xiaogang Su <xiaogan...@gmail.com> >Cc: arun <smartpink...@yahoo.com>; R help <r-help@r-project.org>; Rui Barradas ><ruipbarra...@sapo.pt> >Sent: Saturday, February 23, 2013 11:23 PM > >Subject: Re: [R] Selecting First Incidence from Longitudinal Data > > >Hi >Thank you very much, but I forgot to tell that I also want to include the >patients for which no complication occurred. That is, for my data I want to >include patient no. 4, for which the COMPL value will be 0. > >In that case, what R function should I write? > > > > >On Sat, Feb 23, 2013 at 12:23 PM, Xiaogang Su <xiaogan...@gmail.com> wrote: > >My bad. I didn't try it out with the real data. Here you go. HTH, X >> >> >>dat <- read.table(text=" >>ID COMPL SEX HEREDITY >>1 0 1 2 >>1 0 1 2 >>1 3 1 2 >>2 0 0 1 >>2 1 0 1 >>2 2 0 1 >>2 2 0 1 >>3 0 0 1 >>3 0 0 1 >>3 0 0 1 >>3 0 0 1 >>3 2 0 1 >>4 0 1 2 >>4 0 1 2 >>", header = TRUE) >> >> >>dat0 <- dat[dat$COMPL!=0, ] >>dat0$sequence <- as.vector(unlist(lapply(aggregate(dat0$ID, >>by=list(dat0$ID),FUN=length)$x, FUN=function(x){seq(1, x)}))) >>dat0 <- dat0[dat0$sequence==1, ] >>dat0 >> >> >> >> >>On Sat, Feb 23, 2013 at 2:09 PM, arun <smartpink...@yahoo.com> wrote: >> >>HI, >>>Tried your approach: >>> >>> >>> dat1$sequence <- as.vector(unlist(lapply( aggregate(dat1$ID, >>>by=list(dat1$ID),FUN=length)$x, FUN=function(x){seq(1, x)}))) >>> dat0 <- dat1[dat1$sequence==1 & dat1$COMPL!= 0, ] #your second solution >>> dat0 >>>#[1] ID COMPL SEX HEREDITY sequence >>>#<0 rows> (or 0-length row.names) >>> >>> >>>dat1[dat1$sequence==1,] #here the OP wanted first incidence where COMPL!=0 >>># ID COMPL SEX HEREDITY sequence >>>#1 1 0 1 2 1 >>>#4 2 0 0 1 1 >>>#8 3 0 0 1 1 >>>#13 4 0 1 2 1 >>>A.K. >>> >>> >>> >>> >>>----- Original Message ----- >>>From: Xiaogang Su <xiaogan...@gmail.com> >>>To: Rui Barradas <ruipbarra...@sapo.pt> >>>Cc: r-help@r-project.org >>>Sent: Saturday, February 23, 2013 2:15 PM >>>Subject: Re: [R] Selecting First Incidence from Longitudinal Data >>> >>>Try this: >>>dat$sequence <- as.vector(unlist(lapply( aggregate(dat$ID, by=list(x), >>>FUN=length)$x, FUN=function(x){seq(1, x)))) >>>dat0 <- dat[dat$sequence==1, ] >>> >>>HTH, X >>> >>> >>>On Sat, Feb 23, 2013 at 1:07 PM, Rui Barradas <ruipbarra...@sapo.pt> wrote: >>> >>>> Hello, >>>> >>>> You can use ?aggregate and ?head to do what you want. Try the following. >>>> >>>> >>>> >>>> dat <- read.table(text=" >>>> >>>> ID COMPL SEX HEREDITY >>>> 1 0 1 2 >>>> 1 0 1 2 >>>> 1 3 1 2 >>>> 2 0 0 1 >>>> 2 1 0 1 >>>> 2 2 0 1 >>>> 2 2 0 1 >>>> 3 0 0 1 >>>> 3 0 0 1 >>>> 3 0 0 1 >>>> 3 0 0 1 >>>> 3 2 0 1 >>>> 4 0 1 2 >>>> 4 0 1 2 >>>> ", header = TRUE) >>>> >>>> aggregate(. ~ ID, data = subset(dat, COMPL != 0), head, 1) >>>> >>>> >>>> Hope this helps, >>>> >>>> Rui Barradas >>>> >>>> Em 23-02-2013 14:28, Tasnuva Tabassum escreveu: >>>> >>>> I have a longitudinal competing risk data of the form: >>>>> >>>>> ID COMPL SEX HEREDITY >>>>> 1 0 1 2 >>>>> 1 0 1 2 >>>>> 1 3 1 2 >>>>> 2 0 0 1 >>>>> 2 1 0 1 >>>>> 2 2 0 1 >>>>> 2 2 0 1 >>>>> 3 0 0 1 >>>>> 3 0 0 1 >>>>> 3 0 0 1 >>>>> 3 0 0 1 >>>>> 3 2 0 1 >>>>> 4 0 1 2 >>>>> 4 0 1 2. >>>>> >>>>> Where, COMPL= health complication of diabetic patients which has value >>>>> labels as 0= no complication,1=coronary heart disease, 2=retinopathy, >>>>> 3= >>>>> nephropathy. >>>>> >>>>> >>>>> I want to select only the first complication that occurred to each >>>>> patient. >>>>> What R function can I use? >>>>> >>>>> [[alternative HTML version deleted]] >>>>> >>>>> ______________________________**________________ >>>>> R-help@r-project.org mailing list >>>>> https://stat.ethz.ch/mailman/**listinfo/r-help<https://stat.ethz.ch/mailman/listinfo/r-help> >>>>> PLEASE do read the posting guide http://www.R-project.org/** >>>>> posting-guide.html <http://www.R-project.org/posting-guide.html> >>> >>>>> and provide commented, minimal, self-contained, reproducible code. >>>>> >>>>> >>>> ______________________________**________________ >>>> R-help@r-project.org mailing list >>>> https://stat.ethz.ch/mailman/**listinfo/r-help<https://stat.ethz.ch/mailman/listinfo/r-help> >>>> PLEASE do read the posting guide http://www.R-project.org/** >>>> posting-guide.html <http://www.R-project.org/posting-guide.html> >>> >>>> and provide commented, minimal, self-contained, reproducible code. >>>> >>> >>> >>> >>>-- >>>============================== >>>Xiaogang Su, Ph.D. >>>Associate Professor & Statistician >>>School of Nursing, University of Alabama >>>Birmingham, AL 35294-1210 >>>(205) 934-2355 [Office] >>>x...@uab.edu >>>xiaogan...@gmail.com >>>https://sites.google.com/site/xgsu00/ >>> >>> >>> [[alternative HTML version deleted]] >>> >>>______________________________________________ >>>R-help@r-project.org mailing list >>>https://stat.ethz.ch/mailman/listinfo/r-help >>>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >>>and provide commented, minimal, self-contained, reproducible code. >>> >>> >> >> >> >>-- >>============================== >>Xiaogang Su, Ph.D. >>Associate Professor & Statistician >>School of Nursing, University of Alabama >>Birmingham, AL 35294-1210 >>(205) 934-2355 [Office] >>x...@uab.edu >>xiaogan...@gmail.com >>https://sites.google.com/site/xgsu00/ > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.