Hi Jim, Try either of the following (untested):
sum( x[1, ] < 12 & x[2, ] > 12) sum(apply(x, 2, function(x) x[1] < 12 & x[2] > 12)) where "x" is your 2x1000 matrix. HTH, Jorge.- On Tue, Mar 19, 2013 at 12:03 AM, Jim Silverton <> wrote: > Hi, > I have a 2 x 10000 matrix of confidence intervals. The first column is the > lower and the next column is the upper. I want to cont how many times a > number say 12 lies in the interval. Can anyone assist? > > -- > Thanks, > Jim. > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
