Hi Arun, Thank u so much for your help. It helped me solve the problem THANK YOU
-Yashvardhan Kajaria On Thu, Mar 14, 2013 at 11:28 PM, arun <smartpink...@yahoo.com> wrote: > HI, > > 1. > > date1<-c("5 jan 2013", "1 jan 2013") > date1<-as.Date(date1,format="%d %b %Y") > date1[1]-date1[2] > #Time difference of 4 days > > > 2. > > > If you only have the week number of year without any other information, it > would be difficult to predict which day that would be. > You could get the week number from the date: > library(lubridate) > date2<-"2013-01-26" > wday(ymd(date2),label=TRUE) > # 1 parsed with %Y-%m-%d > #[1] Sat > > > week(ymd(date2)) > # 1 parsed with %Y-%m-%d > #[1] 4 > A.K. > > ----- Original Message ----- > From: yash kajaria <yash.kaja...@gmail.com> > To: r-help@r-project.org > Cc: > Sent: Thursday, March 14, 2013 9:45 AM > Subject: [R] date & time manipulation- R 2.15.1 windows 7 > > Hi, > I wanted to learn how to solve a date and time manipulation where i can > do the following two > 1. difference of two dates eg (differnce between 5th jan 2013 and 1st > jan 2013) > > 2.Suppose i have week number of the year, i want to know if i can find > out the day it refers to eg( say week 2 of 2013 would be 6th jan 2013 and > the day is sunday) > i need my result to tell me that its the 6th of jan 2013 as well as > the day (sunday) > > Can u please help me out? > > Thanks, > Yashvardhan Kajaria > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.