thank you all.
the dcast formulation is what I am looking for. That version of the
formula A+D ~ H
also works with the original cast function.
result.cast <- cast(A+D ~ H, value="M", data=meltTest)
It generalizes to a four-factor example, as requested.
This ftable solution didn't do what I wanted because it didn't retain A and
D as factors.
On Mon, Mar 18, 2013 at 6:00 PM, Charles Berry <ccbe...@ucsd.edu> wrote:
> Richard M. Heiberger <rmh <at> temple.edu> writes:
>
> >
> > ## Can someone suggest a simpler expression than either of these, with
> the
> > goal
> > ## of taking a long matrix into a wide one with exactly one of the
> factors
> > converted to
> > ## columns and all the rest retained as factors. I want something that
> > generalizes beyond
> > ## the three factors illustrated here.
> >
> > ## Rich
> >
> > meltTest <- data.frame(A=rep(c("B","C"), each=12),
> > D=rep(c("E","F","G"), each=4, times=2),
> > H=rep(c("I","J","K","L"), times=6),
> > M=1:24)
> >
>
> amat <- ftable( xtabs( M ~ A + D + H, meltTest ),row.vars=1:2 )
>
> amat is such a matrix with a few attributes added.
>
> HTH,
>
> Chuck
>
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