Hello,
That's not a very good way of posting your data, preferably paste the
output of ?dput in a post.
Some thing along the lines of the following might do what you want. It
seems that the groups are established by 'dn' and 'obs' numbers. If so, try
# Make up some data
dat <- data.frame(dn = 4, obs = rep(1:5, each = 6), mth = NA)
dat$mth[6] <- 487
dat$mth[9] <- 488
dat$mth[18] <- 488
dat$mth[21] <- 489
dat$mth[30] <- 489
sp <- split(dat, list(dat$dn, dat$obs))
names(sp) <- NULL
tmp <- lapply(sp, function(x){
idx <- which(!is.na(x$mth))[1]
x$mth <- x$mth[idx]
x
})
do.call(rbind, tmp)
Hope this helps,
Rui Barradas
Em 06-04-2013 11:33, Leask, Graham escreveu:
Dear List members
I have a large dataset organised in choice groups see sample below
+-------------------------------------------------------------------------------------------------+
| dn obs choice acid br date cdate
situat~n mth year set |
|-------------------------------------------------------------------------------------------------|
1. | 4 1 0 LOSEC 1 . .
. . 1 |
2. | 4 1 0 NEXIUM 2 . .
. . 1 |
3. | 4 1 0 PARIET 3 . .
. . 1 |
4. | 4 1 0 PROTIUM 4 . .
. . 1 |
5. | 4 1 0 ZANTAC 5 . .
. . 1 |
|-------------------------------------------------------------------------------------------------|
6. | 4 1 1 ZOTON 6 23aug2000 01:00:00 23aug2000
NS 487 2000 1 |
7. | 4 2 0 LOSEC 1 . .
. . 2 |
8. | 4 2 0 NEXIUM 2 . .
. . 2 |
9. | 4 2 1 PARIET 3 25sep2000 01:00:00 25sep2000
L 488 2000 2 |
10. | 4 2 0 PROTIUM 4 . .
. . 2 |
|-------------------------------------------------------------------------------------------------|
11. | 4 2 0 ZANTAC 5 . .
. . 2 |
12. | 4 2 0 ZOTON 6 . .
. . 2 |
13. | 4 3 0 LOSEC 1 . .
. . 3 |
14. | 4 3 0 NEXIUM 2 . .
. . 3 |
15. | 4 3 0 PARIET 3 . .
. . 3 |
|-------------------------------------------------------------------------------------------------|
16. | 4 3 0 PROTIUM 4 . .
. . 3 |
17. | 4 3 0 ZANTAC 5 . .
. . 3 |
18. | 4 3 1 ZOTON 6 20sep2000 00:00:00 20sep2000
R 488 2000 3 |
19. | 4 4 0 LOSEC 1 . .
. . 4 |
20. | 4 4 0 NEXIUM 2 . .
. . 4 |
|-------------------------------------------------------------------------------------------------|
21. | 4 4 1 PARIET 3 27oct2000 00:00:00 27oct2000
NL 489 2000 4 |
22. | 4 4 0 PROTIUM 4 . .
. . 4 |
23. | 4 4 0 ZANTAC 5 . .
. . 4 |
24. | 4 4 0 ZOTON 6 . .
. . 4 |
25. | 4 5 0 LOSEC 1 . .
. . 5 |
|-------------------------------------------------------------------------------------------------|
26. | 4 5 0 NEXIUM 2 . .
. . 5 |
27. | 4 5 0 PARIET 3 . .
. . 5 |
28. | 4 5 0 PROTIUM 4 . .
. . 5 |
29. | 4 5 0 ZANTAC 5 . .
. . 5 |
30. | 4 5 1 ZOTON 6 23oct2000 03:00:00 23oct2000
NS 489 2000 5 |
I wish to fill in the missing values in each choice set - delineated by dn
(Doctor) obs (Observation number) and choices (1 to 6).
For each choice set one choice is chosen which contains full time information
for that choice set ie in set 1 choice 6 was chosen and
shows the month 487. The other 5 choices show mth as missing. I want to fill
these with the correct mth.
I am sure there must be an elegant way to do this in R?
Best wishes
Graham
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
