Hello,
Sorry, forgot the instruction to read in the data.
Now the complete code.
x <- scan(text = "
90.1194354
87.94788274
80.34744843
64.06080347
30.40173724
0
0
0
0
0
16.28664495
23.88707926
29.31596091
48.85993485
13.02931596
0
0
0
7.600434311
20.62975027
29.31596091
32.5732899
")
x
grp <- cumsum(abs(c(0, diff(x == 0))))
tmp <- lapply(split(x, grp), function(x) if(all(x == 0)) NULL else x)
tmp[sapply(tmp, function(x) !is.null(x))]
Rui Barradas
Em 18-04-2013 12:24, Rui Barradas escreveu:
Hello,
Something like this?
grp <- cumsum(abs(c(0, diff(x == 0))))
tmp <- lapply(split(x, grp), function(x) if(all(x == 0)) NULL else x)
tmp[sapply(tmp, function(x) !is.null(x))]
Hope this helps,
Rui Barradas
Em 18-04-2013 10:33, Igor Mintz escreveu:
hello
i have a very long column of numbers. i want R to make a new column every
time the value changes from zero.
example for the column:
90.1194354
87.94788274
80.34744843
64.06080347
30.40173724
0
0
0
0
0
16.28664495
23.88707926
29.31596091
48.85993485
13.02931596
0
0
0
7.600434311
20.62975027
29.31596091
32.5732899
for this example i want to get 3 columns.
thanks!
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.