On 02-05-2013, at 08:28, Sachinthaka Abeywardana <sachin.abeyward...@gmail.com> wrote:
> Hi all, > > I have a feeling the most efficient way to do the following is to use > apply, but I'm still wrapping my head around the function. > > k=matrix(1:6,nrow=3) > > div=1:2 > > > Questions is how do I get R to divide the first column by 1 (div[1]) and > the second column by 2 (div[2]) > > k/div treats k as a vector and does the following (not what I want) > >> k/div > > > [,1] [,2] > [1,] 1 2 > [2,] 1 5 > [3,] 3 3 k / rep(div,each=nrow(k)) Berend ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
