HI GG,
I thought you were referring about the solution that I sent today. Sorry, I
didn't check it.
TRy this:
dat1<- read.table(text="
patient_id number responsed_at delais scores1 scores2
scores3
1 1 2010-05-26 NA 2.6
0.5 0.7
1 2 2010-07-07 42 2.5
NA NA
1 3 2010-08-14 38 2.3
NA NA
1 4 2010-10-01 48 2.5
0.7 0.6
1 5 2010-12-01 61 2.5
NA NA
2 1 2011-07-19 NA 2.5
0.8 0.5
2 2 2011-09-22 65 2.6
NA NA
2 3 2011-10-26 34 2.7
NA NA
3 1 2011-07-17 NA 2.8
0.5 0.6
3 2 2011-10-30 103 2.6
NA NA
3 3 2011-12-23 54 2.5
NA NA
",sep="",header=TRUE,stringsAsFactors=FALSE)
dat1$idx<-with(dat1,ifelse(is.na(delais)|delais<45 &
delais>20, 1,ifelse(delais<60 &
delais>=45,2,ifelse(delais<=90 & delais>=60,3,NA))))
#deleted lines
dat1[as.logical(with(dat1,ave(idx,patient_id,FUN=function(x)
cumsum(is.na(x))))),-8]
# patient_id number responsed_at delais scores1 scores2 scores3
#10 3 2 2011-10-30 103 2.6 NA NA
#11 3 3 2011-12-23 54 2.5 NA NA
nrow(dat1[as.logical(with(dat1,ave(idx,patient_id,FUN=function(x)
cumsum(is.na(x))))),-8])
#[1] 2
#or
table(with(dat1,ave(idx,patient_id,FUN=function(x) cumsum(is.na(x)))))[2]
#1
#2
#added lines
datSub<-dat1[!as.logical(with(dat1,ave(idx,patient_id,FUN=function(x)
cumsum(is.na(x))))),]
#count
sum(with(datSub,idx[idx>1 & !is.na(idx)])-1)
#[1] 5
A.K.
________________________________
From: GUANGUAN LUO <guanguan...@gmail.com>
To: arun <smartpink...@yahoo.com>
Sent: Wednesday, May 22, 2013 11:30 AM
Subject: Re: how to calculate the mean in a period of time?
Hi Arun,
I meant to say "number of observations you have deleted".
In the table, you have deleted some lines which have a delais > 90 days, and
added some lines copied from the precedent lines. Can I calculate the number of
lines that you have deleted and the number of lines that you have added?
GG
2013/5/22 arun <smartpink...@yahoo.com>
Hi GG,
>It is not clear what you meant by "number of observations you have detected".
>Is it the number of observations in the initial dataset for each patient_id?
>Number of observations added also means what? In the final result, we are
>taking the means for each 3 observations keeping the t="0" along with the
>first cluster for each Patient_id.
>
>
>
>
>
>________________________________
>From: GUANGUAN LUO <guanguan...@gmail.com>
>To: arun <smartpink...@yahoo.com>
>Sent: Wednesday, May 22, 2013 11:13 AM
>
>Subject: Re: how to calculate the mean in a period of time?
>
>
>
>Hello A.K,
>for this reconstructed table, can i calculate the number of the observations
>you have delected and the number of the observations that you have added?
>Thanks
>
>GG
>
>
>2013/5/17 arun <smartpink...@yahoo.com>
>
>
>>
>>Hi,
>>Try this:
>>
>> dat1$idx<-with(dat1,ifelse(is.na(delais)|delais<45 &
>>delais>20, 1,ifelse(delais<60 &
>>delais>=45,2,ifelse(delais<=90 & delais>=60,3,NA))))
>>dat1$idx1<-c(dat1$idx[-head(dat1$idx,1)],1)
>>
>>library(zoo)
>>res1<-do.call(rbind,lapply(split(dat1,dat1$patient_id),function(x)
>>{x$idx[as.logical(cumsum(is.na(x$idx)))]<-NA; x1<-x[!is.na(x$idx),];
>>x1[,6:8]<-na.locf(x1[,6:8]);x1$idx1[is.na(x1$idx1)]<-1;
>>x2<-x1[rep(seq_len(nrow(x1)),x1$idx1),];
>>x2$delais[duplicated(x2$delais,fromLast=FALSE)]<-0;
>>x2$t<-seq(0,nrow(x2)-1,1);x2[,-c(8:9)]}))
>> row.names(res1)<- 1:nrow(res1)
>> res2<- res1[,c(1:3,8,4:7)]
>> res2
>>
>># patient_id number responsed_at t delais scores1 scores2 scores3
>>#1 1 1 2010-05-26 0 NA 2.6 0.5 0.7
>>#2 1 2 2010-07-07 1 42 2.5 0.5 0.7
>>#3 1 3 2010-08-14 2 38 2.3 0.5 0.7
>>#4 1 3 2010-08-14 3 0 2.3 0.5 0.7
>>
>>#5 1 4 2010-10-01 4 48 2.5 0.7 0.6
>>#6 1 4 2010-10-01 5 0 2.5 0.7 0.6
>>#7 1 4 2010-10-01 6 0 2.5 0.7 0.6
>>
>>#8 1 5 2010-12-01 7 61 2.5 0.7 0.6
>>#9 2 1 2011-07-19 0 NA 2.5 0.8 0.5
>>#10 2 1 2011-07-19 1 0 2.5 0.8 0.5
>>#11 2 1 2011-07-19 2 0 2.5 0.8 0.5
>>
>>#12 2 2 2011-09-22 3 65 2.6 0.8 0.5
>>#13 2 3 2011-10-26 4 34 2.7 0.8 0.5
>>#14 3 1 2011-07-17 0 NA 2.8 0.5 0.6
>>A.K.
>>
>>________________________________
>>From: GUANGUAN LUO <guanguan...@gmail.com>
>>To: arun <smartpink...@yahoo.com>
>>Sent: Friday, May 17, 2013 9:33 AM
>>
>>Subject: Re: how to calculate the mean in a period of time?
>>
>>
>>
>>Hello，
>>Thank you for your help
>>the lines added to the tables are the precedent lines but not the followed
>>lines, if i just change x2<-x1[rep(seq_len(nrow(x1)-1), is that ok? and so
>>the delais should be changed too, isn't it?
>>
>>
>>GG
>>
>>
>>2013/5/17 arun <smartpink...@yahoo.com>
>>
>>Hi,
>>>No problem.
>>>
>>>Arun
>>>
>>>
>>>
>>>
>>>
>>>
>>>________________________________
>>>From: GUANGUAN LUO <guanguan...@gmail.com>
>>>To: arun <smartpink...@yahoo.com>
>>>Sent: Friday, May 17, 2013 4:19 AM
>>>
>>>Subject: Re: how to calculate the mean in a period of time?
>>>
>>>
>>>
>>>Ah, yes, that is the wrong thing i have written. Thank you so much. the
>>>output which you have got is right.
>>>Thanks a lot.
>>>GG
>>>
>>>
>>>2013/5/16 arun <smartpink...@yahoo.com>
>>>
>>>Hi,
>>>>The output you showed is not clear especially the for the scores3,
>>>>
>>>> 2 2 2011-09-22 3 65
>>>>2.6 0.8 0.8
>>>>2 3 2011-10-26 4 34
>>>>2.7 0.8 0.8
>>>>3 1 2011-07-17 0 NA 2.8
>>>> 0.5 0.6
>>>>In the input data, the scores3 column didn't had 0.8.
>>>>
>>>>
>>>>This is what I got:
>>>>dat1<- read.table(text="
>>>>
>>>>patient_id number responsed_at delais scores1 scores2
>>>> scores3
>>>> 1 1 2010-05-26 NA 2.6
>>>> 0.5 0.7
>>>> 1 2 2010-07-07 42 2.5
>>>> NA NA
>>>> 1 3 2010-08-14 38 2.3
>>>> NA NA
>>>> 1 4 2010-10-01 48 2.5
>>>> 0.7 0.6
>>>> 1 5 2010-12-01 61 2.5
>>>> NA NA
>>>>2 1 2011-07-19 NA 2.5
>>>> 0.8 0.5
>>>>2 2 2011-09-22 65 2.6
>>>> NA NA
>>>>2 3 2011-10-26 34
>>>>2.7 NA NA
>>>>3 1 2011-07-17 NA 2.8
>>>> 0.5 0.6
>>>>3 2 2011-10-30 103 2.6
>>>> NA NA
>>>>3 3 2011-12-23 54
>>>>2.5 NA NA
>>>>",sep="",header=TRUE,stringsAsFactors=FALSE)
>>>>
>>>> dat1$idx<-with(dat1,ifelse(is.na(delais)|delais<45 & delais>20,
>>>>1,ifelse(delais<60 & delais>=45,2,ifelse(delais<=90 & delais>=60,3,NA))))
>>>>library(zoo)
>>>>res<-do.call(rbind,lapply(split(dat1,dat1$patient_id),function(x)
>>>>{x$idx[as.logical(cumsum(is.na(x$idx)))]<-NA; x1<-x[!is.na(x$idx),];
>>>>x1[,6:8]<-na.locf(x1[,6:8]);x2<-x1[rep(seq_len(nrow(x1)),x1$idx),];
>>>>x2$delais[duplicated(x2$delais,fromLast=TRUE)]<-0;
>>>>x2$t<-seq(0,nrow(x2)-1,1);x2}))
>>>>
>>>>
>>>>row.names(res)<- 1:nrow(res)
>>>> res1<- res[,c(1:3,9,4:7)]
>>>>res1
>>>># patient_id number responsed_at t delais scores1 scores2 scores3
>>>>#1 1 1 2010-05-26 0 NA 2.6 0.5 0.7
>>>>#2 1 2 2010-07-07 1 42 2.5 0.5 0.7
>>>>#3 1 3 2010-08-14 2 38 2.3 0.5 0.7
>>>>#4 1 4 2010-10-01 3 0 2.5 0.7 0.6
>>>>#5 1 4 2010-10-01 4 48 2.5 0.7 0.6
>>>>#6 1 5 2010-12-01 5 0 2.5 0.7 0.6
>>>>#7 1 5 2010-12-01 6 0 2.5 0.7 0.6
>>>>#8 1 5 2010-12-01 7 61 2.5 0.7 0.6
>>>>#9 2 1 2011-07-19 0 NA 2.5 0.8 0.5
>>>>#10 2 2 2011-09-22 1 0 2.6 0.8 0.5
>>>>#11 2 2 2011-09-22 2 0 2.6 0.8 0.5
>>>>#12 2 2 2011-09-22 3 65 2.6 0.8 0.5
>>>>#13 2 3 2011-10-26 4 34 2.7 0.8 0.5
>>>>#14 3 1 2011-07-17 0 NA 2.8 0.5 0.6
>>>>
>>>>A.K.
>>>>
>>>>________________________________
>>>>From: GUANGUAN LUO <guanguan...@gmail.com>
>>>>To: arun <smartpink...@yahoo.com>
>>>>Sent: Thursday, May 16, 2013 12:05 PM
>>>>
>>>>Subject: Re: how to calculate the mean in a period of time?
>>>>
>>>>
>>>>
>>>>
>>>>Hello, AK,
>>>>now i have a problem really complicated for me,
>>>>
>>>>Now my table is like this:
>>>>
>>>>patient_id number responsed_at delais scores1 scores2
>>>> scores3
>>>> 1 1 2010-05-26 NA 2.6
>>>> 0.5 0.7
>>>> 1 2 2010-07-07 42 2.5
>>>> NA NA
>>>> 1 3 2010-08-14 38 2.3
>>>> NA NA
>>>> 1 4 2010-10-01 48 2.5
>>>> 0.7 0.6
>>>> 1 5 2010-12-01 61 2.5
>>>> NA NA
>>>>2 1 2011-07-19 NA 2.5
>>>> 0.8 0.5
>>>>2 2 2011-09-22 65 2.6
>>>> NA NA
>>>>2 3 2011-10-26 34
>>>>2.7 NA NA
>>>>3 1 2011-07-17 NA 2.8
>>>> 0.5 0.6
>>>>3 2 2011-10-30 103 2.6
>>>> NA NA
>>>>3 3 2011-12-23 54
>>>>2.5 NA NA
>>>>
>>>>explications: delais = the date of "responsed_at" - the date of precedent
>>>>"responsed_at"
>>>>scores1 is measured every month
>>>>scores2 and 3 are measured every three months
>>>>
>>>>first thing is : if the 20<delais <45, this count one month of delais
>>>>if the 45<=delais <60, this count two month of delais,so add one line with
>>>>the copy of the precedent line,and change the delais to 0
>>>>
>>>>if the 60 <= delais <=90, this count three month of delais, so add two
>>>>lines with the copy of the precedent line,and change these two delais to 0
>>>>
>>>>if the delais >90, delete all the following lines
>>>>
>>>>and add a column "t", "t" means the month, "t" is in order
>>>>
>>>>second thing is :
>>>>I want to replace NA of scores2 and scores3 with the precedent scores
>>>>
>>>>and finally get a table like this:
>>>>
>>>>patient_id number responsed_at t delais scores1
>>>>scores2 scores3
>>>> 1 1 2010-05-26 0 NA 2.6
>>>> 0.5 0.7 # scores2 and 3 are mesured every 3
>>>> 1 2 2010-07-07 1 42 2.5
>>>> 0.5 0.7 ## months,replace the following with
>>>>precedent numbers
>>>> 1 3 2010-08-14 2 38 2.3
>>>> 0.5 0.7 # copy this line
>>>>1 3 2010-08-14 3 0 2.3
>>>> 0.5 0.7 # add one line here and change delais to 0
>>>> 1 4 2010-10-01 4 48 2.5
>>>> 0.7 0.6
>>>>1 4 2010-10-01 5 0
>>>>2.5 0.7 0.6
>>>>1 4 2010-10-01 6 0
>>>>2.5 0.7 0.6
>>>> 1 5 2010-12-01 7 61
>>>>2.5 0.7 0.6
>>>>2 1 2011-07-19 0 NA 2.5
>>>> 0.8 0.5
>>>>2 1 2011-07-19 1 0 2.5
>>>> 0.8 0.5
>>>>2 1 2011-07-19 2 0 2.5
>>>> 0.8 0.5
>>>>2 2 2011-09-22 3 65 2.6
>>>> 0.8 0.8
>>>>2 3 2011-10-26 4 34
>>>>2.7 0.8 0.8
>>>>3 1 2011-07-17 0 NA 2.8
>>>> 0.5 0.6
>>>>(3 2 2011-10-30 103
>>>>2.6 0.5 0.6)# delete these 2 line
>>>>
>>>>
>>>>(3 3 2011-12-23 54
>>>>2.5 0.5 0.6) ## and delete the following lines of this
>>>>patient because the delais is 103 which superior to 90
>>>>
>>>>
>>>>
>>>>Do you know how can i get this?
>>>>Thank you so much
>>>>
>>>>GG
>>>>
>>>>
>>>>2013/5/9 GUANGUAN LUO <guanguan...@gmail.com>
>>>>
>>>>Hello,
>>>>>Because according to the database, the first time of collecting the data
>>>>>is just for an entry, an inclusion of the patients. What i should focus on
>>>>>is the difference between two month. If i don't include the t0, i think i
>>>>>will lose the information. I don't know if this is pertinent.
>>>>>Thank you very much for your help, AK
>>>>>
>>>>>GG
>>>>>
>>>>>
>>>>>
>>>>>2013/5/9 arun <smartpink...@yahoo.com>
>>>>>
>>>>>HI GG,
>>>>>>I did the code according the calculation shown by you. For example, in
>>>>>>the first case, you had scores of (0+1+2+3)/4, which is not 3 months.
>>>>>>It is 3+ initial month. After that it is only 3 months that is
>>>>>>repeating. So, my code is doing this:
>>>>>> 1st group (the scores)
>>>>>>(0+1+2+3)/4
>>>>>>2nd group( scores)
>>>>>>(5+6+7)/3
>>>>>>3rd group
>>>>>>(8+9+10)/3
>>>>>>
>>>>>>Here, the months are used only for illustration. I am taking the mean of
>>>>>>the scores.
>>>>>>
>>>>>>So, if you are only doing every 3 months, why do you need to combine the
>>>>>>initial scores with the first 3 months? Anyway, I did what you asked for.
>>>>>>
>>>>>>
>>>>>>Regards,
>>>>>>Arun
>>>>>>
>>>>>>
>>>>>>________________________________
>>>>>>From: GUANGUAN LUO <guanguan...@gmail.com>
>>>>>>To: arun <smartpink...@yahoo.com>
>>>>>>Sent: Thursday, May 9, 2013 4:19 AM
>>>>>>
>>>>>>Subject: Re: how to calculate the mean in a period of time?
>>>>>>
>>>>>>
>>>>>>
>>>>>>Hi,Thank you so much for your help. I have seen your code. It's very
>>>>>>complicated. The time 0 is the beginning of collecting all the
>>>>>>information.
>>>>>>
>>>>>>The time 1 is the first month when follow the patients, time 2 is the
>>>>>>second month ect. If i want to calculate the means of every 3 month do
>>>>>>you think i should do like this?
>>>>>>
>>>>>>GG
>>>>>>
>>>>>>2013/5/7 arun <smartpink...@yahoo.com>
>>>>>>
>>>>>>Hi,
>>>>>>>Your question is still not clear.
>>>>>>>May be this helps:
>>>>>>>
>>>>>>>dat2<- read.table(text="
>>>>>>>
>>>>>>>patient_id t scores
>>>>>>>1 0 1.6
>>>>>>>1 1 2.6
>>>>>>>1 2 2.2
>>>>>>>1 3 1.8
>>>>>>>2 0 2.3
>>>>>>>2 2 2.5
>>>>>>>2 4 2.6
>>>>>>>2 5 1.5
>>>>>>>",sep="",header=TRUE)
>>>>>>>
>>>>>>>library(plyr)
>>>>>>> dat2New<-ddply(dat2,.(patient_id),summarize,t=seq(min(t),max(t)))
>>>>>>> res<-join(dat2New,dat2,type="full")
>>>>>>>res1<-do.call(rbind,lapply(split(res,res$patient_id),function(x)
>>>>>>>{x1<-x[x$t!=0,];do.call(rbind,lapply(split(x1,((x1$t-1)%/%3)+1),function(y)
>>>>>>> {y1<-if(any(y$t==1)) rbind(x[x$t==0,],y) else y;
>>>>>>>data.frame(patient_id=unique(y1$patient_id),scores=mean(y1$scores,na.rm=TRUE))})
>>>>>>> ) }))
>>>>>>> row.names(res1)<-1:nrow(res1)
>>>>>>>res1$period<-with(res1,ave(patient_id,patient_id,FUN=seq))
>>>>>>> res1
>>>>>>># patient_id scores period
>>>>>>>#1 1 2.05 1
>>>>>>>#2 2 2.40 1
>>>>>>>#3 2 2.05 2
>>>>>>>
>>>>>>>
>>>>>>>A.K.
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>________________________________
>>>>>>>From: GUANGUAN LUO <guanguan...@gmail.com>
>>>>>>>To: arun <smartpink...@yahoo.com>
>>>>>>>Sent: Tuesday, May 7, 2013 11:29 AM
>>>>>>>Subject: Re: how to calculate the mean in a period of time?
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>Yes ， as you have said, probably , it's not continuous.
>>>>>>>
>>>>>>>
>>>>>>>2013/5/7 arun <smartpink...@yahoo.com>
>>>>>>>
>>>>>>>Hi,
>>>>>>>>Your question is not clear. You mentioned to calculate the mean of 3
>>>>>>>>months, but infact you added the scores for t=0,1,2,3 as first 3
>>>>>>>>months, then possibly 4,5,6 as the next. So, it is not exactly three
>>>>>>>>months. Isn't it?
>>>>>>>>
>>>>>>>>
>>>>>>>>Dear R experts,
>>>>>>>>sorry to trouble you again.
>>>>>>>>My data is like this now :
>>>>>>>>patient_id t scores
>>>>>>>>1 0 1.6
>>>>>>>>1 1 2.6
>>>>>>>>1 2 2.2
>>>>>>>>1 3 1.8
>>>>>>>>2 0 2.3
>>>>>>>>2 2 2.5
>>>>>>>>2 4 2.6
>>>>>>>>2 5 1.5
>>>>>>>>
>>>>>>>>I want to calculate the mean of period of 3 months, just get a table
>>>>>>>>like this
>>>>>>>>
>>>>>>>>patient_id period scores
>>>>>>>>1 1 2.05
>>>>>>>>(1.6+2.6+2.2+1.8)/4
>>>>>>>>2 1 2.4
>>>>>>>>(2.3+2.5)/2
>>>>>>>>2 2 2.05
>>>>>>>>(2.6+1.5)/2
>>>>>>>>
>>>>>>>>thank you in avance
>>>>>>>>
>>>>>>>
>>>>>>
>>>>>
>>>>
>>>
>>
>
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