Hello,
Yes, you can do it like you say. Or you can unsort first and multiply later.
mat5.1 <- sapply(seq_len(ncol(ord)), function(i) mat4[order(ord[,i]), i])
multip<-mat4*2
mat5.2 <- sapply(seq_len(ncol(ord)), function(i) multip[order(ord[,i]), i])
identical(mat5.1*2, mat5.2) #TRUE
Also, it's better if you Cc the list, for others to read and eventually
find it of some use.
Rui Barradas
Em 15-06-2013 12:48, Ola Cabaj escreveu:
Thanks, that helps a lot! I got another question, if you don't mind.
If I would like to multiply mat4 by a number/vector
multip<-mat4*2
so to unsort this multiplied matrix I have to change mat4 to multip?
mat5 <- sapply(seq_len(ncol(ord)), function(i) multip[order(ord[,i]), i])
2013/6/15 Rui Barradas <ruipbarra...@sapo.pt <mailto:ruipbarra...@sapo.pt>>
Hello,
If I understand it correctly, the following should sort all columns
of matrix3 and then unsort the sorted matrix.
ord <- apply(matrix3, 2, order)
# sort matrix3
mat4 <- sapply(seq_len(ncol(ord)), function(i) matrix3[ord[,i], i])
mat4
# unsort mat4
mat5 <- sapply(seq_len(ncol(ord)), function(i) mat4[order(ord[,i]), i])
identical(matrix3, mat5) # TRUE
Hope this helps,
Rui Barradas
Em 15-06-2013 11:36, Ola Cabaj escreveu:
I would like to sort matrix3, so that every column in output
matrix is
sorted. Also I have to "unsort" it later on.
matrix1<-matrix(rnorm(100,354,__78),ncol=10)
matrix2<-matrix(rnorm(100,225,__102),ncol=10)
matrix3<-cbind(matrix1,__matrix2)
nrCol<-length(matrix3[1,])
class1<-1:10
for(i in 1:nrCol)
{
sorted.matrix<-matrix3[order(__matrix3[class1,i]),]
}
for(i in 1:liczbaKolumn)
{
output<-sorted.matrix[order(__matrix3[class1,i]),]
}
--
Aleksandra Cabaj
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