HI, set.seed(28) dat1<- as.data.frame(matrix(sample(c(NA,1:20),100,replace=TRUE),ncol=10))
set.seed(49) dat2<- as.data.frame(matrix(sample(c(NA,40:80),100,replace=TRUE),ncol=10)) lapply(seq_len(ncol(dat1)),function(i) {lm(dat2[,i]~dat1[,i])}) #works bcz the default setting removes NA Regarding the options: ?lm() na.action: a function which indicates what should happen when the data contain ‘NA’s. The default is set by the ‘na.action’ setting of ‘options’, and is ‘na.fail’ if that is unset. The ‘factory-fresh’ default is ‘na.omit’. Another possible value is ‘NULL’, no action. Value ‘na.exclude’ can be useful. lapply(seq_len(ncol(dat1)),function(i) {lm(dat2[,i]~dat1[,i],na.action=na.exclude)}) #or lapply(seq_len(ncol(dat1)),function(i) {lm(dat2[,i]~dat1[,i],na.action=na.omit)}) lapply(seq_len(ncol(dat1)),function(i) {lm(dat2[,i]~dat1[,i],na.action=na.fail)}) #Error in na.fail.default(list(`dat2[, i]` = c(54L, 59L, 50L, 64L, 40L, : # missing values in object In your case, the error is different. It could be something similar to the below case: dat1[,1]<- NA lapply(seq_len(ncol(dat1)),function(i) {lm(dat2[,i]~dat1[,i],na.action=na.omit)}) #Error in lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) : # 0 (non-NA) cases # here it is different lapply(seq_len(ncol(dat1)),function(i) {try(lm(dat2[,i]~dat1[,i]))}) #works in the above case. It may not work in your case. You need to provide a reproducible example to understand the situation better. A.K. ----- Original Message ----- From: iza.ch1 <iza....@op.pl> To: r-help@r-project.org Cc: Sent: Saturday, July 27, 2013 8:47 AM Subject: [R] linear fit function with NA values Hi Quick question. I am running a multiple regression function for each column of two data sets. That means as a result I get several coefficients. I have a problem because data that I use for regression contains NA. How can I ignore NA in lm function. I use the following code for regression: OLS<-lapply(seq_len(ncol(es.w)),function(i) {lm(es.w[,i]~es.median[,i])}) as response I get Error in lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) : all values NA thanks for help :) ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.