I have a dataFrame
sID <- c("a", "1,2,3", "b", "4,5,6")
rID <- c("shr1125", "bwr331", "bwr330", "vjhr1022")
tmp <- data.frame(cbind(sID,rID))
but I need to split tmp$sID into three different columns, filling locations
where tmp$sID has only one value with NA.
I can split tmp$sID by the comma
tmp.1 <- strsplit(tmp$sID, ",")
but I can't figure out how to convert the resulting list into a dataFrame.
Ideally, tmp will become four columns wide, something like
sID.a sID.b sID.c rID
NA NA a shr1125
1 2 3 bwr331
NA NA b bwr330
4 5 6 vjhr1022
Thoughts or suggestions?
I tried
havecomma - grep(',', tmp$sID)
for( i in 1:nrow(tmp)){
if (!(tmp[i,] %in% havecomma)){
tmp$sID[i] <- paste(', ,', tmp$sID[i], sep="")
}
}
and thought that I might be able to force the list into a dataframe once
each component had three items, but it just seemed to apply the paste()
function to everything which gave me a list with varying numbers of items.
I'm stuck.
Thanks for your help -
SR
Steven H. Ranney
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