Dear Peter,

the call works for me; e.g.

x <- matrix(rnorm(100), ncol = 4)
heatmap.2(x, dendrogram="none", Colv = FALSE, Rowv = FALSE)

There seems to be something wrong with your matrix z ...

Best,
Matthias

Peter Scacheri wrote:
Thanks Matthias,

I tried that, but received the following error message:

Error in image.default(1:nc, 1:nr, x, xlim = 0.5 + c(0, nc), ylim = 0.5 + :
        dimensions of z are not length(x)(+1) times length(y)(+1)


-Peter

At 10:18 AM +0200 5/15/08, Matthias Kohl wrote:
Dear Peter,

heatmap.2(z, dendrogram = "none", Rowv = FALSE, Colv = FALSE)

should do what you want.

Best,
Matthias

Peter Scacheri wrote:
Using the heatmap.2 function, I am trying to generate a heatmap of a 2 column x 500 row matrix of numeric values. I would like the 1st column of the matrix sorted from the highest to the lowest values - so that the colors reflected in the first column of the heatmap (top to bottom) go from red to green.

After sorting the matrix (z), I tried the following command, but the data remains clustered.

heatmap.2((z),col=greenred(100),dendrogram=NULL,Rowv=FALSE)

I also tried the following, but the data remained clustered.

heatmap.2((z),col=greenred(100),Colv=1:ncol(z))

ANY IDEAS??
Thanks so much,
Peter

______________________________________________
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______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

--
Dr. Matthias Kohl
www.stamats.de

______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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