On Sep 13, 2013, at 9:38 AM, Lutfor Rahman wrote:

Dear forum members,

Please help me understanding significance value when GLM done in r.

After doing minimal adequate model, I have found a number of independent values which are significant. But doing their anova significant values are different. Please find my result following. Which significant values should
I use.


glm(formula = richness ~ moistcont + orgmatter + baresoil + grass10 +
   wood10 + rdnet10 + moistcont:orgmatter + moistcont:baresoil +
grass10:wood10 + grass10:rdnet10 + wood10:rdnet10, family = poisson,
   data = data)

Deviance Residuals:
    Min        1Q    Median        3Q       Max
-1.19112  -0.33682   0.09813   0.32808   0.70509

Coefficients:
                    Estimate Std. Error z value Pr(>|z|)
(Intercept)         11.384447   4.014170   2.836  0.00457 **
moistcont           -0.095813   0.084995  -1.127  0.25962
orgmatter           -1.810116   0.613688  -2.950  0.00318 **
baresoil            -1.636707   0.559129  -2.927  0.00342 **
grass10             -0.018979   0.065647  -0.289  0.77250
wood10               0.150683   0.128386   1.174  0.24053
rdnet10             -0.011448   0.068090  -0.168  0.86648
moistcont:orgmatter  0.025698   0.011521   2.231  0.02571 *
moistcont:baresoil   0.044110   0.015799   2.792  0.00524 **
grass10:wood10       0.010740   0.006498   1.653  0.09838 .
grass10:rdnet10      0.011013   0.004412   2.496  0.01255 *
wood10:rdnet10      -0.088297   0.027120  -3.256  0.00113 **

The only p-value I would have expected to be the same would have been the last one in the avova output:

                   Df Deviance Resid. Df Resid. Dev Pr(>Chi)
.....
wood10:rdnet10       1  10.7812         6      3.928 0.001025 **

And that particular p-value is not far off from the 0.00113 value reported in the model summary. The other p-values are not of the same sort. The p-values above are basically reporting the "significance" of removing single predictors or interactions from the full model. The anova reported below is perfoming sequential addition of terms to a NULL model as well as doing a different test: LR tests instead of Wald statistics.

--
David.


---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

(Dispersion parameter for poisson family taken to be 1)

   Null deviance: 36.1673  on 17  degrees of freedom
Residual deviance:  3.9276  on  6  degrees of freedom
AIC: 97.893

Number of Fisher Scoring iterations: 4

anova(data1, test="Chisq")
Analysis of Deviance Table

Model: poisson, link: log

Response: richness

Terms added sequentially (first to last)


                   Df Deviance Resid. Df Resid. Dev Pr(>Chi)
NULL                                   17     36.167
moistcont            1   8.6322        16     27.535 0.003303 **
orgmatter            1   2.1244        15     25.411 0.144966
baresoil             1   0.0029        14     25.408 0.956986
grass10              1   1.5251        13     23.883 0.216842
wood10               1   3.6952        12     20.187 0.054570 .
rdnet10              1   0.0001        11     20.187 0.990564
moistcont:orgmatter  1   2.0482        10     18.139 0.152381
moistcont:baresoil   1   2.8730         9     15.266 0.090076 .
grass10:wood10       1   0.1431         8     15.123 0.705247
grass10:rdnet10      1   0.4141         7     14.709 0.519883
wood10:rdnet10       1  10.7812         6      3.928 0.001025 **
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

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Alameda, CA, USA

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