On Dec 17, 2013, at 5:53 PM, Simon Kiss wrote: > I think I'm missing something. I have a data frame that looks below. > sample.df<-data.frame(var1=rbinom(50, size=1, prob=0.5), var2=rbinom(50, > size=2, prob=0.5), var3=rbinom(50, size=3, prob=0.5), var4=rbinom(50, size=2, > prob=0.5), var5=rbinom(50, size=2, prob=0.5)) > > I'd like to run a series of univariate general linear models where var1 is > always the dependent variable and each of the other variables is the > independent. Then I'd like to summarize each in a table. > I've tried : > > sample.formula=list(var1~var2, var1 ~var3, var1 ~var4, var1~var5) > mapply(glm, formula=sample.formula, data=list(sample.df), family='binomial') > > And that works pretty well, except, I'm left with a matrix that contains all > the information I need. I can't figure out how to use summary() properly on > this information to usefully report that information.
The default for mapply's SIMPLIFY argument is TRUE. If you do not want a matrix, then set it to FALSE and the list items will retain their glm-object status. (The summary function applied to the resulting list is still a bit strange, but it is recognizable as having class 'glm' at the end. You should be able to extract the bits that you want and ignore the strange $call item.) -- David Winsemius Alameda, CA, USA ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.