Hi are you really sure that age in Younger is factor? If it was numeric you can post process result of merge to get rid of NA
Younger$age<-as.numeric(as.character(Younger$age)) Warning message: NAs introduced by coercion komplet<-merge(Elder, Younger, all=T) komplet[complete.cases(komplet),] ID age 1 ID1 38 2 ID2 35 3 ID3 31 5 ID4 29 6 ID5 21 If it **is** a factor like in your example > str(Younger) 'data.frame': 3 obs. of 2 variables: $ ID : Factor w/ 3 levels "ID3","ID4","ID5": 2 3 1 $ age: Factor w/ 3 levels "21","29","NA": 2 1 3 you can do it in similar way but not so easy. Petr > -----Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- > project.org] On Behalf Of kingsly > Sent: Friday, January 17, 2014 6:14 AM > To: r-help@r-project.org > Subject: Re: [R] Doubt in simple merge > > Thank you dear friends. You have cleared my first doubt. > > My second doubt: > I have the same data sets "Elder" and "Younger". Elder <- data.frame( > ID=c("ID1","ID2","ID3"), > age=c(38,35,31)) > Younger <- data.frame( > ID=c("ID4","ID5","ID3"), > age=c(29,21,"NA")) > > > Row ID3 comes in both data set. It has a value (31) in "Elder" while > "NA" in "Younger". > > I need output like this. > > ID age > ID1 38 > ID2 35 > ID3 31 > ID4 29 > ID5 21 > > Kindly help me. > > > > On Thursday, 16 January 2014 9:16 PM, Marc Schwartz-3 [via R] <ml- > node+s789695n4683682...@n4.nabble.com> wrote: > > Not quite: > > > rbind(Elder, Younger) > ID age > 1 ID1 38 > 2 ID2 35 > 3 ID3 31 > 4 ID4 29 > 5 ID5 21 > 6 ID3 31 > > Note that ID3 is duplicated. > > > Should be: > > > merge(Elder, Younger, by = c("ID", "age"), all = TRUE) > ID age > 1 ID1 38 > 2 ID2 35 > 3 ID3 31 > 4 ID4 29 > 5 ID5 21 > > > He wants to do a join on both "ID" and "age" to avoid duplications of > rows when the same ID and age occur in both data frames. If the same > column names (eg "Var") appears in both data frames and are not part of > the 'by' argument, you end up with Var.x and Var.y in the result. > > In the case of two occurrences of the same ID but two different ages, > if that is possible, both rows would be added to the result using the > above code. > > Regards, > > Marc Schwartz > > > On Jan 16, 2014, at 9:04 AM, Frede Aakmann Tøgersen <[hidden email]> > wrote: > > ________________________________ > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. > > > > > ________________________________ > > If you reply to this email, your message will be added to the > discussion below: http://r.789695.n4.nabble.com/Doubt-in-simple-merge- > tp4683671p4683682.html > To start a new topic under R help, email ml- > node+s789695n78969...@n4.nabble.com > To unsubscribe from R help, click here. > NAML > > > > -- > View this message in context: http://r.789695.n4.nabble.com/Doubt-in- > simple-merge-tp4683671p4683718.html > Sent from the R help mailing list archive at Nabble.com. > [[alternative HTML version deleted]] ________________________________ Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. 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