Hello A. k. thanks for the suggestion. I tried this but it does not work. I probably use it in the wrong way. This is what it tells me,
do.call(rbind,lapply(bank.list,function(x) x[x[,"p_made"]==406,])) Errore in match.names(clabs, names(xi)) : names do not match previous names What am I doing wrong? f. ---------------------------------- Francesca Pancotto Università degli Studi di Modena e Reggio Emilia Palazzo Dossetti - Viale Allegri, 9 - 42121 Reggio Emilia Office: +39 0522 523264 Web: https://sites.google.com/site/francescapancotto/ ---------------------------------- Il giorno 04/feb/2014, alle ore 16:42, arun <smartpink...@yahoo.com> ha scritto: > Hi, > Try: > > If `lst1` is the list: > do.call(rbind,lapply(lst1,function(x) x[x[,"p_made"]==406,])) > A.K. > > > > > On Tuesday, February 4, 2014 8:53 AM, Francesca > <francesca.panco...@gmail.com> wrote: > Dear Contributors > sorry but the message was sent involuntary. > I am asking some advice on how to solve the following problem. > I have a list composed of 78 elements, each of which is a matrix of factors > and numbers, similar to the following > > bank_name date px_last_CIB Q.Y p_made p_for > 1 CIB 10/02/06 1.33 p406-q406 406 406 > 2 CIB 10/23/06 1.28 p406-q406 406 406 > 3 CIB 11/22/06 1.28 p406-q406 406 406 > 4 CIB 10/02/06 1.35 p406-q107 406 107 > 5 CIB 10/23/06 1.32 p406-q107 406 107 > 6 CIB 11/22/06 1.32 p406-q107 406 107 > > > Each of these matrixes changes for the column name bank_name and for the > suffix _CIB which reports the name as in bank_name. Moreover each matrix as > a different number of rows, so that I cannot transform it into a large > matrix. > > I need to create a matrix made of the rows of each element of the list that > respect the criterium > that the column p_made is = to 406. > I need to pick each of the elements of each matrix that is contained in the > list elements, that satisfy this condition. > > It seems difficult to me but perhaps is super easy. > Thanks for any help you can provide. > > Francesca > > > > On 4 February 2014 12:42, Francesca <francesca.panco...@gmail.com> wrote: > >> Dear Contributors >> I am asking some advice on how to solve the following problem. >> I have a list composed of 78 elements, each of which is a matrix of >> factors and numbers, similar to the following >> >> bank_name date px_last_CIB Q.Y p_made p_for >> 1 CIB 10/02/06 1.33 p406-q406 406 406 >> 2 CIB 10/23/06 1.28 p406-q406 406 406 >> 3 CIB 11/22/06 1.28 p406-q406 406 406 >> 4 CIB 10/02/06 1.35 p406-q107 406 107 >> 5 CIB 10/23/06 1.32 p406-q107 406 107 >> 6 CIB 11/22/06 1.32 p406-q107 406 107 >> >> >> -- >> >> Francesca >> >> ---------------------------------- >> Francesca Pancotto, PhD >> Università di Modena e Reggio Emilia >> Viale A. Allegri, 9 >> 40121 Reggio Emilia >> Office: +39 0522 523264 >> Web: https://sites.google.com/site/francescapancotto/ > >> ---------------------------------- >> > > > > -- > > Francesca > > ---------------------------------- > Francesca Pancotto, PhD > Università di Modena e Reggio Emilia > Viale A. Allegri, 9 > 40121 Reggio Emilia > Office: +39 0522 523264 > Web: https://sites.google.com/site/francescapancotto/ > ---------------------------------- > > [[alternative HTML version deleted]] > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]]
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