Hello, If you mean replacing 0 by the average of non-zero values, I guess one way is:
> a[a==0] <- mean(a[a!=0]) Maybe some senior user might correct it. Regards, Pascal On 6 February 2014 12:05, ce <zadi...@excite.com> wrote: > > Dear all, > > My data is : > > a <- > c(0.9721,0.9722,0.9730,0.9723,0.0,0.0,0.0,0.9706,0.9698,0.0,0.9710,0.9699) > > I want to replace zeros with average of before and after values of them. > But sometimes there is one zero sometimes more than one. What is the most > elegant way to do this ? > Thanks a lot > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Pascal Oettli Project Scientist JAMSTEC Yokohama, Japan ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
