Hello,
Maybe with some simple modifications of swiss2. (Note that your 2nd
function wasn't returning a value.)
swiss2 <- function(m, data){
for (i in seq_len(ncol(m))){
data <- gsub(paste(m[,i], sep=",")[1],paste(m[,i], sep=",")[2], data,
ignore.case=F, perl = F, fixed = F, useBytes = F)
}
data
}
swiss2(m, d.data$V1)
[1] "aezAezuezUeZoeZOe"
Hope this helps
Rui Barradas
Em 01-03-2014 21:45, Tobias Kisch escreveu:
Hi everybody
I guess my problem is pretty easy to solve, but I didn't manage to get it
working...
Me, as a Swiss, I'm trying to substitute German "Umlauts" (ä, ü, ö) in a
string variable in a dataset; meaning "ä" to "ae", "ü", to "ue" and "ö" to
"oe".
Here's a reproducible example:
# defining dataset
d.data <- as.data.frame(cbind(c("äzÄzüzÜZöZÖ"), c(rnorm(1))))
# defining "Umlauts"
a <- c("ä", "ae")
A <- c("Ä", "Ae")
u <- c("ü", "ue")
U <- c("Ü", "Ue")
o <- c("ö", "oe")
O <- c("Ö", "Oe")
# Matrix of substitutions
m <- cbind(a,A,u,U,o,O, deparse.level=0)
I’m trying to write a function that does replace the "Umlauts" by the
appropriate substitute. Here's what I have so far:
swiss1 <- function(m, data){
gsub(paste(m[,1], sep=",")[1],paste(m[,1], sep=",")[2], data,
ignore.case=T, perl = F, fixed = F, useBytes = F)
}
test1 <- swiss1(m, d.data$V1)
test1
test
[1] "aezaezüzÜZöZÖ"
Apparently this does substitute the first elements of my matrix m. But i
want it to walk through the whole matrix m. So I thought of doing a for loop
inside the function.
swiss2 <- function(m, data){
for (i in ncol(m)){
gsub(paste(m[,i], sep=",")[1],paste(m[,i], sep=",")[2], data,
ignore.case=T, perl = F, fixed = F, useBytes = F)
}
}
test2<- swiss2(m, d.data$V1)
test2
test2
NULL
What I get then is an empty vector, instead of the original data with the
substituted "Umlauts"
Does anybody has a hint..?
Thanx very much!
Best, Tobi
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