If you don't need a 'running average', there are other 'smoothers' you can
look at. Try 'supsmu':
> set.seed(1)
> x = c(0,1, 3,3.4, 5, 10, 11.23)
> y = x**2 + rnorm(length(x))
> rbind(x, y)
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
x 0.0000000 1.000000 3.000000 3.40000 5.00000 10.00000 11.2300
y -0.6264538 1.183643 8.164371 13.15528 25.32951 99.17953 126.6003
>
> #plot the data
> plot(x, y, type = 'o', lwd = 6)
>
> lines(supsmu(x,y,span = .1), col = 'red', lwd = 2)
>
> supsmu(x,y,span = .1)
$x
[1] 0.00 1.00 3.00 3.40 5.00 10.00 11.23
$y
[1] -3.106279 1.953217 12.072208 17.009572 32.880143 103.671955
121.086741
>
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Fri, Mar 28, 2014 at 4:48 AM, Luca Cerone <luca.cer...@gmail.com> wrote:
> Thanks Jim,
> this partially helps (I wasn't aware of the functions you used, which
> are good to know).
> I have two main doubts about your solution though.
> First of all, in my application x is large ~250000 elements and I have
> to repeat this for ~1000 different y vectors; moreover the range of x
> is much larger than the data I have
> (that is, the gaps constitute the majority of the interval), but the
> xs are "locally" dense.
>
> Also I am not sure whether the linear interpolation let me have the
> results I expect. In your solution, the smoothed data seem to pass
> through all my original points,
> that is not what I would expect from a smoothing procedure that
> removes some noise from the data...
>
> Do you have any other suggestion?
> Again thanks for your help;
> Luca
> Luca Cerone
>
> Tel: +34 692 06 71 28
> Skype: luca.cerone
>
>
> On Thu, Mar 27, 2014 at 8:17 PM, jim holtman <jholt...@gmail.com> wrote:
> > Here is one way. I took your data and applied the 'approx' function to
> get
> > evenly spaced values and then 'filter' to create a moving average of a
> > window of size 5.
> >
> >
> > set.seed(1)
> > x = c(0,1, 3,3.4, 5, 10, 11.23)
> > y = x**2 + rnorm(length(x))
> > rbind(x, y)
> >
> > # create 'even' spacing using the 'approx' function
> > steps <- seq(min(x), max(x), length = 100)
> > newData <- approx(x, y, xout = steps)
> >
> > # use filter for running average
> >
> > avg <- filter(newData$y, rep(1/5, 5))
> >
> > #plot the data
> > plot(x, y, type = 'o')
> >
> > lines(newData$x, avg, col = 'red')
> >
> >
> >
> > Jim Holtman
> > Data Munger Guru
> >
> > What is the problem that you are trying to solve?
> > Tell me what you want to do, not how you want to do it.
> >
> >
> > On Thu, Mar 27, 2014 at 12:35 PM, Luca Cerone <luca.cer...@gmail.com>
> wrote:
> >>
> >> Dear all,
> >> I have a vector x and a vector y = f(x).
> >> e.g.
> >>
> >> x = c(0,1, 3,3.4, 5, 10, 11.23)
> >> y = x**2 + rnorm(length(x))
> >>
> >> I would like to apply a moving average to y, knowing that the x values
> >> are not uniformly spaced. How can I do this in R?
> >> What alternatives I have to filter out the noise from Y??
> >>
> >> Thanks in advance for the help!
> >>
> >>
> >>
> >>
> >> Luca Cerone
> >>
> >> Tel: +34 692 06 71 28
> >> Skype: luca.cerone
> >>
> >> ______________________________________________
> >> R-help@r-project.org mailing list
> >> https://stat.ethz.ch/mailman/listinfo/r-help
> >> PLEASE do read the posting guide
> >> http://www.R-project.org/posting-guide.html
> >> and provide commented, minimal, self-contained, reproducible code.
> >
> >
>
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