Here're a couple alternatives if you want to use the index instead of
the variable name:
# Reproducible data frame
a1 <- 1:15
a2 <- letters[1:15]
a3 <- LETTERS[1:15]
a4 <- 15:1
a5 <- letters[15:1]
df <- data.frame(a1, a2, a3, a4, a5)
df
# a1 a2 a3 a4 a5
# 1 1 a A 15 o
# 2 2 b B 14 n
# 3 3 c C 13 m
# 4 4 d D 12 l
# 5 5 e E 11 k
# 6 6 f F 10 j
# 7 7 g G 9 i
# 8 8 h H 8 h
# 9 9 i I 7 g
# 10 10 j J 6 f
# 11 11 k K 5 e
# 12 12 l L 4 d
# 13 13 m M 3 c
# 14 14 n N 2 b
# 15 15 o O 1 a
# Alternate 1
summary(df)
# prints the following but trims the longer summaries:
# a1 a2 a3 a4 a5
# Min. : 1.0 a :1 A :1 Min. : 1.0 a :1
# 1st Qu.: 4.5 b :1 B :1 1st Qu.: 4.5 b :1
# Median : 8.0 c :1 C :1 Median : 8.0 c :1
# Mean : 8.0 d :1 D :1 Mean : 8.0 d :1
# 3rd Qu.:11.5 e :1 E :1 3rd Qu.:11.5 e :1
# Max. :15.0 f :1 F :1 Max. :15.0 f :1
# (Other):9 (Other):9 (Other):9
# Alternate 2
for (i in 1:length(df)) {
print(summary(df[[i]]))
}
# prints the following:
# Min. 1st Qu. Median Mean 3rd Qu. Max.
# 1.0 4.5 8.0 8.0 11.5 15.0
# a b c d e f g h i j k l m n o
# 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
# A B C D E F G H I J K L M N O
# 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
# Min. 1st Qu. Median Mean 3rd Qu. Max.
# 1.0 4.5 8.0 8.0 11.5 15.0
# a b c d e f g h i j k l m n o
# 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
On 2014-03-28 02:32, Jim Lemon wrote:
On 03/28/2014 05:27 PM, Luana Marotta wrote:
Hi all,
I'm trying to find out what is the equivalent in R for the following
Stata
code:
Let's say I have the variables: a1, a2, a3, a4, a5
forvalues i = 1(1)5 {
summary a`i'
}
That is, I want to know how to loop through variables in R.
Hi Luana,
Try this:
for(var in paste("a",1:5,sep="")) print(summary(get(var)))
Jim
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.