Hello,

Use ?sample.

sample(x, 1, prob = x)

Hope this helps,

Rui Barradas

Em 10-04-2014 19:49, Simone Gabbriellini escreveu:
Hello List,

I have an array like:

c(4, 3, 5, 4, 2, 2, 2, 4, 2, 6, 6, 7, 5, 5, 5, 10, 10, 11, 10,
12, 10, 11, 9, 12, 10, 36, 35, 36, 36, 36, 35, 35, 36, 37, 35,
35, 38, 35, 38, 36, 37, 36, 36, 37, 36, 35, 35, 36, 36, 35, 35,
36, 35, 38, 35, 35, 35, 36, 35, 35, 35, 6, 5, 8, 6, 6, 7, 1,
7, 7, 8, 9, 7, 8, 7, 7, 13, 13, 13, 14, 13, 13, 13, 14, 14, 15,
15, 14, 13, 14, 39, 39, 39, 39, 39, 39, 41, 40, 39, 39, 39, 39,
40, 39, 39, 41, 41, 40, 39, 40, 41, 40, 41, 40, 40, 40, 39, 41,
39, 39, 39, 39, 40, 39, 39, 40, 40, 39, 39, 39, 1, 4, 3, 4)

I would like to pick up an element with a probability proportional to
the element value, thus higher values should be picked up more often
than small values (i.e., picking up 38 should be more probable than
picking up 3)

Do you have any idea on how to code such a rich-get-richer mechanism?

Best regards,
Simone


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