I am processing an arbitrary number of XML files and extracting specific nodes. I then create a dataframe for each nodeset. I return a list containing these dataframes.
Example: > str(result)List of 2 $ :'data.frame': 1 obs. of 5 variables: ..$ data-name : chr "Etiologic diagnosis of Acute Febrile Hemorrhagic Syndrome" ..$ valid-time-begin: chr "2014-04-28T01:31:49Z" ..$ valid-time-end : chr "3014-04-28T01:31:48Z" ..$ DvString-dv : chr "Typhoid fever" ..$ language : chr "en-US" $ :'data.frame': 1 obs. of 5 variables: ..$ data-name : chr "Etiologic diagnosis of Acute Febrile Hemorrhagic Syndrome" ..$ valid-time-begin: chr "2014-04-29T01:02:00Z" ..$ valid-time-end : chr "3014-04-29T01:01:59Z" ..$ DvString-dv : chr "Dengue" ..$ language : chr "en-US" I would like to have each of the list items as a row in one dataframe. My attempts so far have been unsuccessful. I have tried t(), merge(), lapply(), etc. Short of some elaborate *for loop* (I know is frowned upon) I am out of answers. I would think this is a fairly common need, maybe even a FAQ that I haven't found yet. Thanks in advance. -- ============================================ Timothy Cook LinkedIn Profile:http://www.linkedin.com/in/timothywaynecook MLHIM http://www.mlhim.org [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
