Sorry I made a copy and paste error. To get all the details of the curves 
between 0 and I had to use:

E <- seq(0,10, len = 2000) 

Sorry for the inconvenience.

Yours sincerely / Med venlig hilsen


Frede Aakmann Tøgersen
Specialist, M.Sc., Ph.D.
Plant Performance & Modeling

Technology & Service Solutions
T +45 9730 5135
M +45 2547 6050
fr...@vestas.com
http://www.vestas.com

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> -----Original Message-----
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Frede Aakmann Tøgersen
> Sent: 23. april 2014 10:54
> To: Andras Farkas; r-help@r-project.org
> Subject: Re: [R] finding value for a parameter in an equation
> 
> Hi Andras
> 
> I suppose you want to find the real root of your equation if such exists for
> the particular settings of the parameters. For that you can use uniroot().
> 
> So define a function based on your equation like this:
> 
> f <- function(E, D1, D2, IC501, IC502, ECON, ALPHA, M1, M2){
>     1 - D1/(IC501*((E/(ECON-E))^(1/M1)))+D2/(IC502*((E/(ECON-E))^(1/M2)))
> +
>         (ALPHA*D1*D2)/(IC501*IC502*((E/(ECON-E))^(0.5/M1+0.5/M2)))
> }
> 
> Now do some plotting to see how the functions behaves:
> 
> ## Parameters
> D1 <-c(0.2,0.6,0.8)
> D2 <-c(114,190,304)
> IC501 <-0.62
> IC502 <-137.8
> ECON <-5.95
> ALPHA <-0.00005
> M1 <-0.84
> M2 <-0.96
> 
> # vector for E
> E <- seq(1,15, len = 100)
> 
> ## three curves for each set of values of D1 and D2
> plot(E, f(E, D1[1], D2[1], IC501, IC502, ECON, ALPHA, M1, M2), type = "l", 
> col =
> "red")
> lines(E, f(E, D1[2], D2[2], IC501, IC502, ECON, ALPHA, M1, M2), type = "l", 
> col
> = "green")
> lines(E, f(E, D1[3], D2[3], IC501, IC502, ECON, ALPHA, M1, M2), type = "l", 
> col
> = "blue")
> 
> f() is only defined on the open interval (0;6).
> 
> Attached figure shows that there is real roots for the 3 values of  D1 and D2
> somewhere between 0 and 1.
> 
> And those can be found as
> 
> > uniroot(f, c(0.0001,1), D1=D1[1], D2=D2[2], IC501=IC501, IC502=IC502,
> ECON=ECON, ALPHA=ALPHA, M1=M1, M2=M2)
> $root
> [1] 0.0003440589
> 
> $f.root
> [1] 21.33889
> 
> $iter
> [1] 14
> 
> $init.it
> [1] NA
> 
> $estim.prec
> [1] 6.103516e-05
> 
> > uniroot(f, c(0.0001,1), D1=D1[2], D2=D2[2], IC501=IC501, IC502=IC502,
> ECON=ECON, ALPHA=ALPHA, M1=M1, M2=M2)
> $root
> [1] 0.3840484
> 
> $f.root
> [1] -9.45929e-05
> 
> $iter
> [1] 9
> 
> $init.it
> [1] NA
> 
> $estim.prec
> [1] 6.103516e-05
> 
> > uniroot(f, c(0.0001,1), D1=D1[3], D2=D2[3], IC501=IC501, IC502=IC502,
> ECON=ECON, ALPHA=ALPHA, M1=M1, M2=M2)
> $root
> [1] 0.1476688
> 
> $f.root
> [1] -0.001927616
> 
> $iter
> [1] 9
> 
> $init.it
> [1] NA
> 
> $estim.prec
> [1] 6.103516e-05
> 
> >
> 
> 
> > uniroot(f, c(0.0001,1), D1=D1[2], D2=D2[2], IC501=IC501, IC502=IC502,
> ECON=ECON, ALPHA=ALPHA, M1=M1, M2=M2)
> $root
> [1] 0.3840484
> 
> $f.root
> [1] -9.45929e-05
> 
> $iter
> [1] 9
> 
> $init.it
> [1] NA
> 
> $estim.prec
> [1] 6.103516e-05
> 
> But
> 
> 
> 
> 
> Yours sincerely / Med venlig hilsen
> 
> 
> Frede Aakmann Tøgersen
> Specialist, M.Sc., Ph.D.
> Plant Performance & Modeling
> 
> Technology & Service Solutions
> T +45 9730 5135
> M +45 2547 6050
> fr...@vestas.com
> http://www.vestas.com
> 
> Company reg. name: Vestas Wind Systems A/S
> This e-mail is subject to our e-mail disclaimer statement.
> Please refer to www.vestas.com/legal/notice
> If you have received this e-mail in error please contact the sender.
> 
> 
> > -----Original Message-----
> > From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org]
> > On Behalf Of Andras Farkas
> > Sent: 22. april 2014 21:33
> > To: r-help@r-project.org
> > Subject: [R] finding value for a parameter in an equation
> >
> > Dear All,
> >
> > please provide some insights for the following:
> >
> > we have:
> >
> > D1 <-c(0.2,0.6,0.8)
> > D2 <-c(114,190,304)
> > IC501 <-0.62
> > IC502 <-137.8
> > ECON <-5.95
> > ALPHA <-0.00005
> > M1 <-0.84
> > M2 <-0.96
> >
> > and the equation:
> >
> > 1 = D1/(IC501*((E/(ECON-E))^(1/M1)))+D2/(IC502*((E/(ECON-
> > E))^(1/M2)))+(ALPHA*D1*D2)/(IC501*IC502*((E/(ECON-
> > E))^(0.5/M1+0.5/M2)))
> >
> > In this equation the value for parameter "E" is what I am trying to 
> > calculate
> > (all other parameters are known) for each pairs of D1 and D2 (ie: input
> D1[1]
> > and D2[1] and the rest of the parameters first then substitute D1[2] and
> > D2[2], then substitute D1[3] and D2[3]). It seems as if the equation can not
> > be re-arranged so that "E" could be directly calculated, so looking to see 
> > if
> > you could help me perhaps with a thought on how this could be solved with
> > R,
> >
> > thanks as always,
> >
> > Andras
> >     [[alternative HTML version deleted]]

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