Hi Kristi,

Try

out1970$smoot

HTH,
Jorge.-


On Fri, May 2, 2014 at 10:00 AM, Kristi Glover <kristi.glo...@hotmail.com>wrote:

> Hi R User,
> I am wonedring how I can extract a part of objects from list.
>
> For example
>
> > str(out1970)
> List of 8
>  $ comm     : num [1:16, 1:57] 1 1 1 1 1 1 1 1 1 1 ...
>   ..- attr(*, "dimnames")=List of 2
>   .. ..$ : chr [1:16] "H_s5" "H_s1" "R_s2" "H_s2" ...
>   .. ..$ : chr [1:57] "Pimephales.promelas" "Semotilus.atromaculatus"
> "Rhinichthys.atratulus" "Pimephales.notatus" ...
>  $ u        : num [1:16, 1:57] 0 0 0 0 0 0 0 0 0 0 ...
>   ..- attr(*, "dimnames")=List of 2
>   .. ..$ : chr [1:16] "H_s5" "H_s1" "R_s2" "H_s2" ...
>   .. ..$ : chr [1:57] "Pimephales.promelas" "Semotilus.atromaculatus"
> "Rhinichthys.atratulus" "Pimephales.notatus" ...
>  $ r        : Named num [1:16] 0.0312 0.0938 0.1562 0.2188 0.2812 ...
>   ..- attr(*, "names")= chr [1:16] "H_s5" "H_s1" "R_s2" "H_s2" ...
>  $ c        : Named num [1:57] 0.00877 0.02632 0.04386 0.0614 0.07895 ...
>   ..- attr(*, "names")= chr [1:57] "Pimephales.promelas"
> "Semotilus.atromaculatus" "Rhinichthys.atratulus" "Pimephales.notatus" ...
>  $ p        : num 1.59
>  $ fill     : num 0.294
>  $ statistic: num 11.4
>  $ smooth   :List of 2
>   ..$ x: num [1:51] 0 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 ...
>   ..$ y: num [1:51] 1 0.887 0.826 0.776 0.732 ...
>  - attr(*, "class")= chr "nestedtemp"
>
>
> I  wanted to extract the value $ x and $y from List of 2 (smooth), but I
> could not extarct it. I used following functions
>
> > sapply(out1970$smooth, "[[",1)
> x y
> 0 1
>
> > sapply(out1970$smooth, "[[",2)
>         x         y
> 0.0200000 0.8869147
> But when I tried to extarct all value using
>
> >sapply(out1970$smooth, "[[",1:51)
> Error in FUN(X[[1L]], ...) : attempt to select more than one element
>
> would you mind to give some suggestions in how I get the value for all
> (1:51) ?
> thanks
> KG
>
>
>
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>
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>

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