Hi Mat,
Try that:
gsub("[A-Za-z]", "", df$A)This is a regular expression that looks for all characters (A to Z and a to z) and replaces it with nothing ("")
You will need to convert the column to numeric after this operation. HTH, Ivan -- Ivan Calandra University of Franche-Comté Laboratoire Chrono-Environnement Bureau ATER -107L 16, Route de Gray 25030 Besançon Cedex, France ivan.calan...@univ-fcomte.fr +33 (0) 381 66 20 60 http://chrono-environnement.univ-fcomte.fr/spip.php?article1830 Le 19/05/14 15:00, Mat a écrit :
Hello togehter, i have a litte problem to convert a data.frame. My data.frame looks like this one A 1 R5000 2 R4800 3 R4700 4 3500 5 3800 I need now a command, which outputs all the numbers, without the character in front. The solution look like this one:A1 5000 2 4800 3 4700 4 3500 5 3800 Thanks. Best regards. Mat -- View this message in context: http://r.789695.n4.nabble.com/substring-if-value-starts-with-a-character-tp4690823.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
