Another option is the plyr package.
library(plyr)
result <- dlply(size, ~ Year +Season, function(.sub){
with(.sub, smooth.spline(Size, Prop, spar = 0.25))
}
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belgium
+ 32 2 525 02 51
+ 32 54 43 61 85
thierry.onkel...@inbo.be
www.inbo.be
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asking him to perform a post-mortem examination: he may be able to say what the
experiment died of.
~ Sir Ronald Aylmer Fisher
The plural of anecdote is not data.
~ Roger Brinner
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that a reasonable answer can be extracted from a given body of data.
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-----Oorspronkelijk bericht-----
Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Namens
jim holtman
Verzonden: dinsdag 20 mei 2014 2:44
Aan: Marlin Keith Cox
CC: r-help@r-project.org
Onderwerp: Re: [R] Subsets of a function
It would have been nice if you at least supplied a subset of the data, but here
is a try at it:
myList <- split(size, list(size$Year, size$Season)) result <- lapply(myList,
function(.sub){
smooth.spline(.sub$Size, spar = 0.25)
})
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Mon, May 19, 2014 at 8:34 PM, Marlin Keith Cox <marlink...@gmail.com>wrote:
> Hi all, this is a reoccurring theme in my programming and I need some
> help with it. When I use a built in function and need to use it on a
> subset of my data frame, I always end up using the subset function
> first, but this seems very clunky. For example, if I have years 2003:2013
> with season "a"
> and "b" within each year, and I want to create a smooth.spline, I end
> up creating a subset for each year and season, and then have a smooth
> spline function for each year and season. Can I do this more efficiently?
>
>
> The subsets are below:
>
>
> size.2003<-subset(size,Year==2003&Season=="a")
>
> size.2004<-subset(size,Year==2004&Season=="a")
>
> size.2005<-subset(size,Year==2005&Season=="a")
>
> size.2006<-subset(size,Year==2006&Season=="a")
>
> size.2007<-subset(size,Year==2007&Season=="a")
>
> size.2008<-subset(size,Year==2008&Season=="a")
>
> size.2009<-subset(size,Year==2009&Season=="a")
>
> size.2010<-subset(size,Year==2010&Season=="a")
>
> size.2011<-subset(size,Year==2011&Season=="a")
>
> size.2012<-subset(size,Year==2012&Season=="a")
>
> size.2013<-subset(size,Year==2013&Season=="a")
>
> size.2003b<-subset(size,Year==2003&Season=="b")
>
> size.2004b<-subset(size,Year==2004&Season=="b")
>
> size.2005b<-subset(size,Year==2005&Season=="b")
>
> size.2006b<-subset(size,Year==2006&Season=="b")
>
> size.2007b<-subset(size,Year==2007&Season=="b")
>
> size.2008b<-subset(size,Year==2008&Season=="b")
>
> size.2009b<-subset(size,Year==2009&Season=="b")
>
> size.2010b<-subset(size,Year==2010&Season=="b")
>
> size.2011b<-subset(size,Year==2011&Season=="b")
>
> size.2012b<-subset(size,Year==2012&Season=="b")
>
> size.2013b<-subset(size,Year==2013&Season=="b")
>
> The smooth.spline is below
>
> 2003<-with(size.2003,smooth.spline(Size,Prop,spar=0.25))
>
> 2004<-with(size.2004,smooth.spline(Size,Prop,spar=0.25))
> 2005<-with(size.2005,smooth.spline(Size,Prop,spar=0.25))
> etc. etc.
>
> M. Keith Cox, Ph.D.
> Principal
> MKConsulting
> 17105 Glacier Hwy
> Juneau, AK 99801
> U.S. 907.957.4606
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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