You may also try: library(reshape2) A2 <- melt(A1) split(A2[,2],A2[,1]) A.K.
On Tuesday, July 8, 2014 12:57 PM, Lorenzo Alfieri <alfio...@hotmail.com> wrote: Hi, I'm trying to find a way to reorder the elements of a list. Let's say I have a list like this: A1<-list(c(1:4),c(2,4,5),23,c(4,5,13)) > A1 [[1]] [1] 1 2 3 4 [[2]] [1] 2 4 5 [[3]] [1] 23 [[4]] [1] 4 5 13 All the elements included in it are values, while each sublist is a time index Now, I'd like to reorder the list (without looping) so to obtain one sublist for each value, which include all the time indices where each value appears. In other words, the result should look like this: >A2 [[1]] [1] 1 [[2]] [1] 1 2 #because value "2" appears in the time index [[1]] and [[2]] of A1 [[3]] [1] 1 [[4]] [1] 1 2 4 [[5]] [1] 2 4 [[13]] [1] 4 [[23]] [1] 3 Any suggestion? Thanks Alfio [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
