Dear Sohail,
Using Jim's data set skdat, two more options would be
# first option
d <- with(skdat, table(ID, lettertag))
names <- colnames(d)
d <- c(list(rownames(d)), lapply(1:ncol(d), function(i) as.numeric(d[,i])))
names(d) <- c('ID', names)
d
# second option
d <- with(skdat, table(ID, lettertag))
res <- c(list(rownames(d)), sapply(apply(d, 2, list), "[", 1))
names(res)[1] <- "ID"
res
HTH,
Jorge.-
On Fri, Aug 15, 2014 at 7:19 PM, Jim Lemon <j...@bitwrit.com.au> wrote:
> On Thu, 14 Aug 2014 06:08:51 PM Sohail Khan wrote:
> > Hi
> > I have data set as follows:
> > A 92315 A 35018 A 56710 B 52700 B 92315 B 15135 C 35018 C
> 52700
> > I would like to transform this data set into:
> > ID 92315 35018 56710 52700 15135 A 1 1 1 0 0 B 1 0 0 1 1 C 0 1 0
> 1 0
> > I looked into reshape package to no avail.
> > I would appreciate any suggestions.
> >
> > -Sohail
> >
> Hi Sohail,
> You are doing a bit more than reshaping. This may get you there:
>
> skdat<-read.table(text="A 92315
> A 35018
> A 56710
> B 52700
> B 92315
> B 15135
> C 35018
> C 52700",stringsAsFactors=FALSE)
> names(skdat)<-c("lettertag","ID")
> ID<-unique(skdat$ID)
> lettertags<-unique(skdat$lettertag)
> newskdat<-list(ID)
> for(i in 1:length(lettertags))
> newskdat[[i+1]]<-
> as.numeric(ID %in% skdat$ID[skdat$lettertag==lettertags[i]])
> names(newskdat)<-c("ID",lettertags)
>
> I'm assuming that you don't really want your answer as a single string.
>
> Jim
>
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