OK , i tried predict(rp,b) but showed me a result which i can't understand, now it's the argument type="vector" worked.
-- PO SU mail: desolato...@163.com Majored in Statistics from SJTU At 2014-11-12 11:55:08, "Bharat Bargujar" <bharatbargu...@gmail.com> wrote: HI, Try this: results <- predict(rp,b,type = "vector") Regards, Bharat On 12 November 2014 09:17, PO SU <rhelpmaill...@163.com> wrote: Dear expeRts, Now i have a train dataset a and test dataset b , i using the following codes: rp<-rpart(y~.,data=a,method="class") plot(rp) text(rp) but how can i use the trained model to predict b? TKS. -- PO SU mail: desolato...@163.com Majored in Statistics from SJTU ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
