The functional form given in the post written by Ssuhanchen captures my
eyes. It is the cumulative distribution function of Poisson when the
number of counts is less than or equal to 2 with unknown parameter
mu=x/2. Since it is a nonlinear function, there may be multiple
solutions but the solution should be greater than 0 (if I am in the
right track). I am assuming this functional form is originated from
the Poisson. Under this assumption, one solution is found as below:
> rt <- uniroot(function(x) ppois(2, lambda=x)-0.05, interval=c(0.5,1),
extendInt="yes")
Warning messages:
1: In ppois(2, lambda = x) : NaNs produced
2: In ppois(2, lambda = x) : NaNs produced
3: In ppois(2, lambda = x) : NaNs produced
> ppois(2, lambda=rt$root)
[1] 0.0500001
> rt$root
[1] 6.295791
Thus, the solution x would be rt$root*2 (Note that I did not try to find
other solutions). I hope this helps.
Chel Hee Lee
On 2/10/2015 2:29 AM, Rolf Turner wrote:
On 10/02/15 14:04, Ssuhanchen wrote:
Hi!
I want to use R to calculate the variable x which is in a complex
equation
in below:
2
Σ[exp(-x/2)*(x^k)/(2^k*k!)]=0.05
k=0
how to solve this equation to get the exact x in R?
Is this homework? Sure looks like it. Talk to your prof. Or do a
bit of work on learning how to use R --- which is presumably the point
of the exercise.
cheers,
Rolf Turner
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