Hi, I've got a complicated grep problem (or not)... I currently have a file with the headings as follows:
DAY MONTH YEAR SA_TUES SA_MON SU_WED CH_TUES CH_WED CH_MON AR_TUES AR_WED AR_MON SA_THUR SU_FRI CH_THUR CH_FRI AR_THUR AR_FRI I want to grep out all columns that have SA at the beginning of their day including any other information pertaining to that day. Ultimately I want to end up with: SA_TUES SA_MON CH_TUES CH_MON AR_TUES AR_MON SA_THUR CH_THUR AR_THUR Is there a way of doing this simply with grep? Or will this need to be more complicated? Thanks! K. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
