Thanks.The code you gave me at the end works correctly.. I was wondering if
there is more efficient way to access each element withouth this classic for
loop.
RegardsAlex
On Wednesday, April 1, 2015 5:54 PM, David Winsemius
<dwinsem...@comcast.net> wrote:
On Apr 1, 2015, at 3:34 AM, Alaios via R-help wrote:
> Dear all,I have a R structure that was created with replicate.The data sets
> looks to be a matrix with each cell being a list.
> str(error_suburban_0[,1],max.level=1)
> List of 4
> $ vaR :List of 20
> ..- attr(*, "class")= chr "variogram"
> $ Shadowing:List of 2
> ..- attr(*, "class")= chr "geodata"
> $ FIT :List of 1
> $ propmodel:List of 12
> ..- attr(*, "class")= chr "lm"
>
>
> The error_suburban is a matrix that each field so
> error_suburban_0[,1], error_suburban_0[,2], error_suburban_0[,3],
> error_suburban_0[,4],... and so on, contains the four sublists
> $ vaR :List of 20
> ..- attr(*, "class")= chr "variogram"
> $ Shadowing:List of 2
> ..- attr(*, "class")= chr "geodata"
> $ FIT :List of 1
> $ propmodel:List of 12
> ..- attr(*, "class")= chr "lm"
>
>
> I would like to pick for each of these matrix elements to collect only the
> $Shadowing sublist
> error_suburban_0[,1], error_suburban_0[,2], error_suburban_0[,3],
> error_suburban_0[,4]... and so on
>
> Right now I am implementing this by a for loop that access each matrix
> element sequentially.
It would have been better to show the results of dim() or dput(). Matrix
objects (which are capable of holding lists) should be accessible with either a
single or double argument to "[". This should deliver contents:
for (i in 1:4) print( error_suburban_0[i]$Shadowing )
If the matrix has 4 or more rows, then that would be accessing only from the
first column. If fewer than 4 rows, you would be wrapping around to later
columns.
--
David.
>
> Can you please advice me if there is a better approach to do that in R?
> Regards
> Alex
>
>
> [[alternative HTML version deleted]]
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--
David Winsemius
Alameda, CA, USA
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