Hi Jim, That solves my problem. Than you.
-- Kumar ᐧ Postdoctoral Associate Fagan Lab, Department of Biology University of Maryland On Tue, Apr 21, 2015 at 5:31 PM, Jim Lemon <drjimle...@gmail.com> wrote: > HI Kumar, > A simple way is: > > phimat<-function(x) { > xcol<-dim(x)[2] > newx<-matrix(NA,nrow=xcol,ncol=xcol) > for(i in 1:xcol) { > for(j in 1:xcol) newx[i,j]<-phi(table(x[,i],x[,j])) > } > rownames(newx)<-colnames(newx)<-colnames(x) > return(newx) > } > phimat(df) > > Jim > > > On Wed, Apr 22, 2015 at 6:34 AM, Kumar Mainali <kpmain...@gmail.com> > wrote: > > I want to calculate phi coefficient for every pair of the columns. Is > there > > a way to generate a matrix like a correlation matrix? I know cor function > > in the case below gives same answer as phi coefficient. > > > > x <- sample(c(0,1), 10, replace=TRUE) > > y <- sample(c(0,1), 10, replace=TRUE) > > z <- sample(c(0,1), 10, replace=TRUE) > > df <- data.frame(x,y,z) > > cor(df) > > library(psych) > > phi(df) > > > > Thank you, > > Kumar Mainali > > Postdoctoral Associate > > Department of Biology > > University of Maryland > > ᐧ > > > > [[alternative HTML version deleted]] > > > > ______________________________________________ > > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.