I *think* you want:
ZC <- do.call(rbind,lapply(a,get))
But why do you make "a" a *list* of names rather than a vector of names?
Generally one uses lists to hold "complicated" structures.
A sequence of character scalars is best stored in an atomic vector.
cheers,
Rolf Turner
P. S. Thank you for providing a reproducible example! :-)
R. T.
On 17/06/15 21:58, Matteo wrote:
Hello R users,
I am trying to run the command rbind gathering the name of tables to bind
from a list argument.
Unfortunately I am not able to obtain it.
I would appreciate any suggestions. Below is a reproducible example with
the problem.
Thanks
Matteo
##############################################################
ZA<-data.frame(x = 1:2, y = 1:10,z=letters[1:5])
ZB<-data.frame(x = 1, y = 5:24,z=letters[2])
a<-as.list(ls(pattern= "^Z?"));a
#############################################################
I_would_like_ZC<-rbind(ZA,ZB) # this is what I would like to have
#############################################################
b<-(paste(a, collapse = ','))
call("rbind",(b)) # I am not able to remove ""
b<-noquote(paste(a, collapse = ','))
call("rbind",(b)) # I am not able to remove ""
--
Technical Editor ANZJS
Department of Statistics
University of Auckland
Phone: +64-9-373-7599 ext. 88276
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