Hi Petr;
Thanks so much. Here are the questions and the dput(A) and dput(B). Basicaly I
have two questions;
> dput(A)structure(list(posA = c(1L, 2L, 5L, 4L, 9L), posB = c(9L, 7L, 12L, 7L,
> 13L)), .Names = c("posA", "posB"), class = "data.frame", row.names = c(NA,
> -5L))> dput(B)structure(list(pos = c(4L, 2L, 7L, 1L, 13L, 12L, 9L), a =
> c(0.4, 0.1, 0.5, 0.4, 0.1, 0.2, 0.3), b = c(7L, 5L, 8L, 1L, 6L, 11L, 12L), c
> = c(0.8, 0.4, 0.32, 0.1, 0.13, 0.01, 0.23)), .Names = c("pos", "a", "b",
> "c"), class = "data.frame", row.names = c(NA, -7L))
Q1) Values in A represent the region of chromosome. I need choose these regions
in B (all region in A are exist in B in a single column) and then summing up
the column "a in B and count the numbers that gives >0.7. For example, consider
the first row in A. They are 1 and 9. After sorting the first column in B then
summing column "a" only between 1 to 9 in sorted B and cut off at >0.7. Then
count how many rows in sorted B gives >0.7. For example there are only 5 rows
between 1 to 9 in sorted B and only summing first 2 of them gives>0.7 . Then
my answer is going to be 2
Q2) What is the min value of B$a for given each intervals in A
Regards,
Oslo
On Monday, June 13, 2016 8:05 AM, PIKAL Petr <petr.pi...@precheza.cz> wrote:
Ok.
Instead of explaining what you have, please send a result of
dput(B) and dput(A)
And set you mail client to send plain text mail otherwise your code is barely
readable.
What do you want to do with printed values?
What is B? From this it seems that it is data frame but then you try to put
sorted data frame into a data frame column.
B$possort=B[order(B$pos),]
With such code and data frame I get an error.
So please try to keep above mentioned when posting a query.
Regards
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of oslo via R-
> help
> Sent: Friday, June 10, 2016 11:09 PM
> To: oslo <o...@yahoo.com>; Jeff Newmiller <jdnew...@dcn.davis.ca.us>;
> oslo via R-help <r-help@r-project.org>; oslo <hok...@yahoo.com>
> Subject: Re: [R] summing up a column.
>
> Jeff;
> thanks for this. My question was job related. No from my course. I need
> finish a job for the place I work. I am so sorry for causing misunderstanding.
> thanks,
> Oslo
>
> On Friday, June 10, 2016 5:08 PM, oslo via R-help <r-help@r-project.org>
> wrote:
>
>
> Jeff thanks for this. My question was job related. No from my course. I need
> finish a job for the place I work. I am so sorry for causing misunderstanding.
> thanks,
> Oslo
>
> On Friday, June 10, 2016 5:02 PM, Jeff Newmiller
> <jdnew...@dcn.davis.ca.us> wrote:
>
>
> Multiple posting happens when you are learning a new system, but reading
> the posting guide can keep the bleeding down.
>
> 1) There is a no-homework policy on this list... different educational
> organizations have different standards for what is acceptable outside help,
> so you should be using the support offered by your instructor or educational
> institution.
>
> 2) Once you have completed your course, you CAN learn to post data with
> your code so that it is self-contained... that is, reproducible on our
> vanilla R
> session. Using the dput function is one excellent strategy.
>
> 3) This is not a problem that needs a loop... as Bert (not Bret) said, you
> can do
> this in one or two statements if you simply use basic logical indexing. If
> your
> instructor wants you to do it with a loop for sine reason then you really
> really
> should not be here... you should be talking to him/her.
> --
> Sent from my phone. Please excuse my brevity.
>
> On June 10, 2016 1:34:03 PM PDT, oslo via R-help <r-help@r-project.org>
> wrote:
> Dear All;
> I had difficulty to post a mail along with appropriate of data structure. I do
> sincerely apologize for multiple posting
>
>
> I would like to sum up the B$a column and cut off at 0.7 for the each row of
> intervals giving in file=A.For example the interval at the first row in
> A$posA
> and A$posB is 1 and 9. So, I need adding up the B$a and cut off B$a>.7 from
> the 1 to 9 in B$pos. And then I need to the same using the intervals in the
> second, third..... rows in A. Obviously my loop is wrong and does not work
> properly. Please help for my this first experience. Regards Here are my
> codes #sorting B$possort=B[order(B$pos),] #Running loop for(i in 1:nrow(A))
> {if(sum(B[a$B, i:A[1:2])>0.7) {print(A[1:i,]) } } Reply, R
> R-help@r-project.org
> mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
>
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>
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