All floating point operations are done to machine precision -- roughly 16 digits. See ?.Machine . You can choose to round, truncate, or display to anything less than that that you care to. See also the digits parameter of ?options
The rest of your post is ambiguous to me. But note that (all?/most?) rng's are vectorized, so e.g. > set.seed(1123) > rnorm(10,mean= runif(10,2,3), sd = runif(10,4,6)) [1] 4.369411 1.944876 3.143913 6.489048 -1.093468 1.330675 -3.936239 11.740755 [9] -2.260413 -1.748759 ... if that's what you meant. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Tue, Aug 2, 2016 at 11:56 AM, Adrian Johnson <oriolebaltim...@gmail.com> wrote: > Dear group, > > I am trying to generate a vector of random numbers for 20K observation. > > however, I want to generate numbers (with 6 decimal places) within the range > of > Std. Dev : 2-3 > mean : 4-6 > > Is there a method to generate numbers with 6 decimal places under > these parameters > > thank you. > Adrian > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
