Hi I wonder what do you want to do with intended output. You can get required numbers by
lll <- split(simD, simD$ID) lapply(lll, function(x) c(min(x[, "MILEAGE"]), diff(x[,"MILEAGE"]))) $A [1] 21548 1030 290 786 $B [1] 30245 1903 1980 1751 3995 251 Then pad it with NA max.l<-max(sapply(res, length)) res2<-lapply(res, function(x) c(x, rep(NA, max.l-length(x)))) $A [1] 21548 1030 290 786 NA NA $B [1] 30245 1903 1980 1751 3995 251 > t(as.data.frame(res2)) [,1] [,2] [,3] [,4] [,5] [,6] A 21548 1030 290 786 NA NA B 30245 1903 1980 1751 3995 251 > After that you should combine it with required values from first data frame and of course you need to name new columns e.g. by loop. If you had it as a list you could work with it easily by R functions or convert it back to your data frame > library (plyr) data.frame(ldply(lll, data.frame), fMileage=unlist(res)) .id ID PRODDATE FAILDATE MILEAGE fMileage A1 A A 2010-02-15 2011-03-20 21548 21548 A2 A A 2010-02-15 2011-03-21 22578 1030 A3 A A 2010-02-15 2011-03-24 22868 290 A4 A A 2010-02-15 2011-03-25 23654 786 B1 B B 2010-02-24 2010-08-23 30245 30245 B2 B B 2010-02-24 2010-09-23 32148 1903 B3 B B 2010-02-24 2010-09-24 34128 1980 B4 B B 2010-02-24 2010-10-23 35879 1751 B5 B B 2010-02-24 2010-11-23 39874 3995 B6 B B 2010-02-24 2010-12-23 40125 251 Cheers Petr > -----Original Message----- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Abhinaba > Roy > Sent: Wednesday, August 10, 2016 11:23 AM > To: r-help <r-help@r-project.org> > Subject: [R] Calculate mileage at each 'faildate' > > Hi R-helpers, > > > - I have a dataframe similar to 'simD'. > > > dput(simD) > structure(list(ID = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L), > .Label = > c("A", "B"), class = "factor"), PRODDATE = structure(c(14655, 14655, 14655, > 14655, 14664, 14664, 14664, 14664, 14664, 14664 ), class = "Date"), FAILDATE = > structure(c(15053, 15054, 15057, 15058, 14844, 14875, 14876, 14905, 14936, > 14966), class = "Date"), > MILEAGE = c(21548L, 22578L, 22868L, 23654L, 30245L, 32148L, > 34128L, 35879L, 39874L, 40125L)), .Names = c("ID", "PRODDATE", > "FAILDATE", "MILEAGE"), row.names = c(NA, -10L), class = "data.frame") > > > - I have split the dataset by 'ID' and sorted the dataframe by > 'faildate' (oldest to newest). > > > > - Now, for each of the splits I want to calculate the 'Mileage' at each > of the 'faildate'. > > > > - The output I desire is 'outD'. > > > > dput(outD) > structure(list(ID = structure(1:2, .Label = c("A", "B"), class = "factor"), > PRODDATE = structure(c(14655, 14664), class = "Date"), MIL_1 = c(21548L, > 30245L), MIL_2 = c(1030L, 1903L), MIL_3 = c(290L, 1980L), > MIL_4 = c(786L, 1751L), MIL_5 = c(NA, 3995L), MIL_6 = c(NA, > 251L)), .Names = c("ID", "PRODDATE", "MIL_1", "MIL_2", "MIL_3", > "MIL_4", "MIL_5", "MIL_6"), row.names = c(NA, -2L), class = "data.frame") > > ***Please note that I have MIL_6 because the max(# failures) in data by ID is > 6 (6 failures for 'B')* > > > - And I would like to extend it to other numeric and date variable as > well. > > > How can I do this in R? > > Best, > Abhinaba > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ________________________________ Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. 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