Dear R-help-community,
I hope, that�s the appropiate channel to post a quastion? For some days I have been struggling with a problem concerning the �survSplit�-function of the package �survival�. Searching the internet I have found a pretty good -German- description of Daniel Wollschl�ger describing how to use survSplit: (https://books.google.de/books?id=9G4oBgAAQBAJ <https://books.google.de/books?id=9G4oBgAAQBAJ&pg=PA345&lpg=PA345&dq=daniel+ wollschl%C3%A4ger+survsplit&source=bl&ots=ajPgInB83d&sig=noQIAXMWe6oQJ-LwsTC kroWdwHQ&hl=de&sa=X&ved=0ahUKEwiqwoX8q83OAhVlM5oKHSMGDrEQ6AEIHjAA#v=onepage& q=daniel%20wollschl%C3%A4ger%20survsplit&f=false> &pg=PA345&lpg=PA345&dq=daniel+wollschl%C3%A4ger+survsplit&source=bl&ots=ajPg InB83d&sig=noQIAXMWe6oQJ-LwsTCkroWdwHQ&hl=de&sa=X&ved=0ahUKEwiqwoX8q83OAhVlM 5oKHSMGDrEQ6AEIHjAA#v=onepage&q=daniel%20wollschl%C3%A4ger%20survsplit&f=fal se Mr. Wollschl�ger also provides the dataset, all of the code he used and an excerpt of his output: > library(survival) # f�r survSplit() > dfSurvCP <- survSplit(dfSurv, cut=seq(30, 90, by=30), end="obsT", + event="status", start="start", id="ID", zero=0) # sortiere nach Beobachtungsobjekt und linken Intervallgrenzen > idxOrd <- order(dfSurvCP$ID, dfSurvCP$start) > head(dfSurvCP[idxOrd, ], n=7) obsT status sex X IV start ID 1 30 0 f -1.3130607 A 0 1 181 60 0 f -1.3130607 A 30 1 361 63 1 f -1.3130607 A 60 1 10 11 1 f -1.2282824 A 0 10 100 27 1 m -0.1018403 B 0 100 101 30 0 m -0.4079027 B 0 101 281 42 1 m -0.4079027 B 30 101 Unfortunaltely when I tried to copy Mr. Wollschl�gers operations using his very dataset, RStudio just returned the following error-message: > dfSurvCP2 <- survSplit(dfSurv,cut=seq(30,90,by=30),end="obsT",event="status",start="start ",id="ID",zero=0) Error in formula.default(eval(parse(text = x, keep.source = FALSE)[[1L]])) : invalid formula I tried to figure out what�s wrong, but so far didn�t find any solutions� I would be very glad if anyone could help me out here. vhfv [[alternative HTML version deleted]]
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