Hello,
I'm not at all sure if the following is what you need but instead of
for (i in length(FD$WEEK))
try
for (i in 1:length(FD$WEEK))
or even better
for (i in seq_len(FD$WEEK))
And use Control[i, 1], not Control[, 1]
Hope thi helps,
Rui Barradas
Citando Christoph Puschmann <c.puschm...@student.unsw.edu.au>:
Hey all,
I would like to know if anyone, can put in the right direction of
the following problem:
I am currently want to use it to check if a column with a length of
61327 is consistent over an 1 to 157 interval until the end of the
column. In the case the interval is interrupted I want to know which
values are missing and where the missing values are located. I
started of with the following code to assign 1s, if we have a number
≤ 157 and 0 if not.
I tried to do a double loop:
n=61327
Control = matrix(
0,
nrow = n,
ncol = 1)
for (i in length(FD$WEEK)) {
for (j in 1:157) {
if(FD$WEEK[j] <= 157) {
Control[,1] = 1
} else {
Control[,1] = 0
}
}
}
I believe that this code is not correct, but I am unable to wrap my
head around how I can check that the interval always will be followed.
All the best,
Christoph
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