Sorry, my mistake, - it works both ways with a correct example and neither
way with the wrong example.
k
On Thu, Jun 26, 2008 at 4:25 PM, Wacek Kusnierczyk <
[EMAIL PROTECTED]> wrote:
> >>> sapply(dats,function(x){sapply(x,min)})
> >>>
> >> you can achieve the same with
> >>
> >> sapply(dats, sapply, min)
> >>
> >>
> >>
> > Did you actually try it?
> >
> >
> >> dats <- data.frame(1:10,2:11)
> >> sapply(dats,sapply,min)
> >>
> > X1.10 X2.11
> > [1,] 1 2
> > [2,] 2 3
> > [3,] 3 4
> > [4,] 4 5
> > [5,] 5 6
> > [6,] 6 7
> > [7,] 7 8
> > [8,] 8 9
> > [9,] 9 10
> > [10,] 10 11
> >
> > Sapply doesn't (or can't?) pass arguments to another sapply -- maybe the
> > trick can be done without an anonymous function but not the way you
> > suggested.
> >
> >
>
> did you actually read the original mail? there dats was a *list* of
> data frames.
> try this:
>
> d = data.frame(a=1:10. b=11:20)
> l = list(a=d, b=d)
> sapply(l, sapply, min)
> sapply(l. function(d) sapply(d, min))
>
> did you actually read the docs for sapply? there ... stands for
> optional arguments to FUN.
> try this:
>
> ?sapply
>
>
> vQ
>
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